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2 years ago

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The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). W

hat is the angular acceleration at t = 5 s?The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). What is the angular acceleration at t = 5 s?'

1 answer:

FromTheMoon [43]2 years ago

4 0

Answer: $\alpha =30-4=26 rad/s^2$

Explanation:

Given

Position of a car is given by

$\theta =t^3-2t^2-4t+10$

and angular speed is $\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega$

angular acceleration is

$\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha$

$\alpha =6t-4$

at $t=5 s$

$\alpha =30-4=26 rad/s^2$

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