Answer: f=150cm in water and f=60cm in air.
Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:
= (nglass - ni)(
-
).
nglass is the index of refraction of the glass;
ni is the index of refraction of the medium you want, water in this case;
R1 is the curvature through which light enters the lens;
R2 is the curvature of the surface which it exits the lens;
Substituting and calculating for water (nwater = 1.3):
= (1.5 - 1.3)(
-
)
= 0.2(
)
f =
= 150
For air (nair = 1):
= (1.5 - 1)(
-
)
f =
= 60
In water, the focal length of the lens is f = 150cm.
In air, f = 60cm.
Answer:
W = 9533.09 Watt
Explanation:
given,
diameter of pipe inlet, d₁ = 10 cm
r₁ = 5 cm
diameter of pipe outlet, d₂ = 15 cm
r₂= 7.5 cm
head upto water level is to rise = 60 + 5
= 65 m
flow rate = 0.015 m³/s
we know
A₁ v₁ = A₂ v₂ = Q
π r₁² v₁ = π r₂² v₂ = 0.015


v₂ = 0.848 m/s
v₁ = 1.908 m/s
Applying Bernoulli's equation
P_p is the pump pressure
Power of the pump
W = P_p x Q
W = 635539.32 x 0.015
W = 9533.09 Watt
Answer:
1.176 N
Explanation:
= mass of the bottle = 0.30 kg
= initial speed of the bottle = 2.8 m/s
= final speed of the bottle = 0 m/s
= stopping distance traveled = 1.0 m
= magnitude of frictional force acting on bottle
Using work-change in kinetic energy theorem
N
direction :
frictional force acts in opposite direction of motion.
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Potential Energy = mass * Hight * acceleration of gravity
PE=hmg
PE = 1.5 * .2 * 9.81
PE = 2.943
it lost .6 so 2.943 - .6 = 2.343
now your new energy is 2.343 so solve for height
2.343 = mhg
2.334 = .2 * h * 9.81
h = 1.194
the ball after the bounce only went up 1.194m