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Answer:
2014.44 N
Explanation:
mass of spacecraft, m = 1850 kg
distance r = 3 x R
where r be the radius of earth.
g be the acceleration due to gravity on the surface of earth and g' be the acceleration due to gravity at height


g' = g / 9
g' = 9.8 / 9 = 1.089 m/s²
Force of gravity on the space craft
F = m g' = 1850 x 1.089
F = 2014.44 N
Thus, the force of gravity on the space craft at height is 2014.44 N.
Charge dQ on a shell thickness dr is given by
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge bound by a spherical surface of radius r)
Gauss's Law states:
(Flux out of surface) = (charge bound by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
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