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Svetlanka [38]
2 years ago
5

A succession of single tones or pitches perceived as a unit is called:

Physics
1 answer:
jeka57 [31]2 years ago
5 0
A succession of single tones or pitches perceived as a unit is called a melody. It is a linear succesion of tones in music that is seen as one single entity. It is a combination of rhythm, pitch and tonal color. Melodies usually has one ormore motifs or phrases that are being repeated all throughout a composition. Melodies are characterized by the melodic motion it posses , the pitch, intervals between the pitches, continuity and pitch range. Due to the a wide range of melodies that can be made from tones, differet genres of music arise. Examples are Jazz, Rock music, Classical, pop, R&B and the like. 
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Answer:

390, right

Explanation:

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Explain the theory Steven Reiss developed and tested.
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Calculate the force of Earth’s gravity on a spacecraft 2.00 Earth radii above the Earth’s surface (That would be 3.00 Earth radi
igomit [66]

Answer:

2014.44 N

Explanation:

mass of spacecraft, m = 1850 kg

distance r = 3 x R

where r be the radius of earth.

g be the acceleration due to gravity on the surface of earth and g' be the acceleration due to gravity at height

\frac{g'}{g}=\left (\frac{R}{r}  \right )^{2}

\frac{g'}{g}=\left (\frac{R}{3R}  \right )^{2}

g' = g / 9

g' = 9.8 / 9 = 1.089 m/s²

Force of gravity on the space craft

F = m g' = 1850 x 1.089

F = 2014.44 N

Thus, the force of gravity on the space craft at height is 2014.44 N.

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2 years ago
A spherically symmetric charge distribution has a charge density given by ρ = a/r , where a is constant. Find the electric field
Airida [17]
Charge dQ on a shell thickness dr is given by 

dQ = (charge density) × (surface area) × dr 

dQ = ρ(r)4πr²dr 

∫ dQ = ∫ (a/r)4πr²dr 

∫ dQ = 4πa ∫ rdr 

Q(r) = 2πar² - 2πa0² 

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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An 8.00 kg point mass and a 15.0 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
Verdich [7]

Answer:a=2.23\times 10^{-9} m/s^2

Explanation:

Given

Mass of first Point mass m_1=8 kg

Mass of second Point m_2=15 kg

distance between them d=50 cm

third point mass m_3=m

Distance between m\ and\ m_1 is\ 20 cm

Distance between  m\ and\ m_2 is 30 cm

Force Due to m_1\ and\ m F_1=\frac{Gmm_1}{d_1^2}

F_1=\frac{8Gm}{(0.2)^2}

F_1=200 mG

F_2=m\frac{Gmm_2}{d_2^2}

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Net Force

F_{net}=F_1-F_2

=200 mG-166.67 mG

=33.33 mG

F_{net}=222.33\times 10^{-11} N

F_{net}=2.23m\times 10^{-9} N

acceleration a=\frac{2.23m\times 10^{-9}}{m}

a=2.23\times 10^{-9} m/s^2

towards 8 kg mass

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2 years ago
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