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choli [55]
2 years ago
11

What is a possible set of quantum numbers for the unpaired electron in the following electron configuration: [Ar] 3d10 4s2 4p5?

a. n=3, ℓ =1, mℓ =−1, ms =+½ b. n=3, ℓ =2, mℓ =−1, ms =−½ c. n=4, ℓ =2, mℓ =−2, ms =+½ d. n=4, ℓ =0, mℓ = 0, ms =+½ e. n=4, ℓ =1, mℓ =−1, ms =+½
Chemistry
1 answer:
Bogdan [553]2 years ago
6 0

Answer:E

Explanation:

The electron is expected to be in any of the 4p orbitals. For the 4p orbitals

n=4

l=1

ml=-1,0,1

ms=-1/2 or +1/2

All the ml and ms configurations are equiprobable hence the answer.

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URGENT!! 50 Points Please Help!! Will mark brainliest!! Assignment due in 30 minutes.
dedylja [7]

a) The least number of decimal points is 0 so you should round the answer to 43.

b) The least number of significant figures is 2 so round to 7.3

c)The least number of decimal places is 1 so round to 225.7

d) The least number of significant figures is 3 so round to 92.0

e) The least number of significant figures is 3 so round to 32.4

f) The least number of decimal places is 0 so round to 104m^3

Basically, for addition and subtraction round to the least number of decimal places found in the factors, and for multiplication and division round to the least number of significant figures found in the factors.

4 0
2 years ago
32. Mercury has an atomic mass of 200.59 amu. Calculate the a. Mass of 3.0 x 1023 atoms. b. Number of atoms in one nanogram of M
Radda [10]

a.200.59 amu of mercury contains = 6.02 * 1023 molecules

Mass for 3.0 * 1023 molecules = (3.0 * 1023 * 200.59) /6.02 * 1023

= 100.29 amu

Thus, mass for 3.0 * 1023 molecules is 100.29 amu

b.As, 200.59 g mercury contains = 6.02 * 1023 atoms

1 g mercury contains = (6.02 * 1023 /200) atoms

= 3.01 * 1021 atoms

Thus, 1 ng mercury contains = (3.01 * 1021) / 109

= 3.01 * 1012 atoms

Thus, 3.0 * 1012 atoms present in 1 ng mercury


6 0
2 years ago
Read 2 more answers
Initially, 50.0 g iron(iii) chloride is present. what amount of fecl3 is this, in moles?
nekit [7.7K]
One mole of a compound contains the mass equivalent to the molecular mass or relative formula mass of the compound.
1 mole of iron iii chloride contains a mass of  162.2 g. 
Therefore, 50 g will contain 50 g/162.2 g = 0.3083 moles
           = 0.3083 moles of Fe2Cl3
8 0
2 years ago
A compound is found to contain 23.3% magnesium, 30.7% sulfur and 46.0% oxygen. What is the empirical formula of this compound?
Nesterboy [21]
Answer:

MgSO_3

Explanation:

As is standard for these sorts of questions, we assume 100 g of substance, and use the percentage elemental compositions to calculate an empirical formula.

"Magnesium" = (23.3*g)/(24.31*g*mol^-1) = 0.958*mol

"Sulfur" = (30.7*g)/(32.06*g*mol^-1) = 0.958*mol

"Oxygen" = (46.0*g)/(15.999*g*mol^-1) = 2.86*mol

We divide thru by the smallest molar quantity (0.958*mol) to get and empirical formula of MgSO_3, magnesium sulfite.

Ordinarily you would not be given the percentage of oxygen by mass. You would be given the percentages of the metal and sulfur, and would have to assume that the balance was oxygen.


Hope this helps!

-Much love, Makayla
6 0
2 years ago
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Classify each material as an alloy or a ceramic. brick, tile, bronze, brass, steel, glass
umka21 [38]

Classify each material as an alloy or ceramic

alloy- Bronze,brass, steel and glass

Ceramic- brick  and tile

<u><em> Explanation</em></u>

<u><em>Alloy</em></u>  is a metal  made up  by combining  two or  more  metallic elements.  

for example, bronze  is made up  by alloying tin with copper.


<u><em>Ceramic  </em></u>materials  is an inorganic,non  metallic which is often crystalline oxide,nitride  or carbide  material.

For example, Tiles are made up of natural clay sand and water.

6 0
2 years ago
Read 2 more answers
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