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Hitman42 [59]
2 years ago
6

To calculate the relative age of rocks, geologists use the rate of radioactive decay of isotopes present in their samples. What

is the term used for the original amount of
the elemental isotopes being investigated?
A rare earth isotopes
B. Son isotopes
C. daughter isotopes
D. parent isotopes
Chemistry
1 answer:
GenaCL600 [577]2 years ago
4 0
A

I have had this question!!
Hope this helps!!!
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A gas has a pressure of 3.16 atm at STP. I have decided to transfer it to a container that is 3 times larger than the original v
Maru [420]

Answer: The new pressure will be 1.1atm

Explanation:

V1 = V

P1 = 3.16atm

V2 = 3V

P2=?

P1V1 =P2V2

3.16 x V = P2 x 3V

P2 = (3.16 x V) /3V

P2 = 1.1atm

7 0
2 years ago
You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain
IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of O_2:-

Mass = 49.8 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

Moles_{O_2}= 1.55625\ mol

Since pressure and volume are constant, we can use the Avogadro's law  as:-

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

n₁ = 0.778125 moles

Moles of carbon dioxide = 0.778125 moles

Molar mass of CO_2 = 44.0 g/mol

Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

5 0
2 years ago
11. A sample contains 25% water and weighs 201 grams. Determine the grams of water in the
77julia77 [94]

Answer:

m_{water}=50.25g

Explanation:

Hello,

In this case, considering that the by-mass percent of water is:

\% m/m=\frac{m_{water}}{m_{sample}}*100\%

Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:

m_{water}=\frac{\%m/m*m_{sample}}{100\%}\\ \\m_{water}=\frac{25\%*201g}{100\%}\\ \\m_{water}=50.25g

Best regards.

5 0
2 years ago
On a separate sheet of paper, write the formulas for the missing components of these neutralization reactions.
Fofino [41]
The  formula  of  the  missing  component  are  a   follows

HBr  +  KOH  ------>  KBr  +  H2O

H2SO4  +  2NH4OH--------> (NH4)2SO4  +  2H2O

2HNO3     +  Mg(OH)2  --------->  Mg(NO3)2  +  2  H2O
4 0
2 years ago
Read 2 more answers
At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

5 0
2 years ago
Read 2 more answers
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