Answer:
The answer is 20 degrees
Step-by-step explanation:
A trapezoid is a quadrilateral with four angles and the sum of the four angles is 360 degrees.
Britton rotated the trapezoid ABCD 180º, but we were not told that he tampered with the angles size or shape, we can now agree that it is still the same trapezoid that was rotated without any alterations in angles, size and shape.
Since we've been given that the angle B is 20º, and the measurement was not altered when rotating the trapezoid. Therefore the angle B' will also be 20º.
I hope this helps.
3x² - 7x - 8 = 0
We're asked about square roots so we won't try to factor; we'll go right for the quadratic formula,
x = ( 7 ± √(7² - 4(3)(-8)) )/(2(3)) = (7 ± √(49+96))/6 = 7/6 ± √145/6
145 = 5×29, so no square factors. The positive difference is
d = (7/6 + √145/6) - (7/6 - √145/6) = 2√145/6 = √145/3
so m=145, n=3 for a sum of
Answer: 148
∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices a
koban [17]
To get the length of each side,
use the distance formula with equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The
right answer is the letter b) triangle ABC and Triangle MNO are Congruent
<span>triangles
ABC and MNO are triangles that have the same lengths of its three sides.
</span>2 The answer is the letter c)
rotation
There
is a rotation of
90º about ABC and MNO the origin is B=N
B=N
C----------O
A----------M
