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ICE Princess25 [194]
2 years ago
4

Select which option best completes the following statement: _____________ can add or subtract features from the __________ backl

og at any time.
Engineering
1 answer:
Musya8 [376]2 years ago
8 0

Answer:

Product owner(s), product

Explanation:

Under normal circumstances, maintenance of product backlog is done when there are multiple teams working on independent products. Each unique combination of team and product should have an independent Product Backlog. At any given time, the product owner(s) can add or remove features from the product backlog. It's important to note that whenever there's new information learned, the product owner should re-prioritize the product backlog.

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3.24 Program: Drawing a half arrow (Java) This program outputs a downwards facing arrow composed of a rectangle and a right tria
eimsori [14]

Answer:

Here is the JAVA program:

import java.util.Scanner; // to get input from user

public class DrawHalfArrow{ // start of the class half arrow

public static void main(String[] args) { // starts of main() function body

    Scanner scnr = new Scanner(System.in); //reads input

int arrowBaseHeight = 0; // stores the height of arrow base

int arrowBaseWidth  = 0; // holds width of arrow base

int arrowHeadWidth = 0; // contains the width of arrow head

// prompts the user to enter arrow base height, width and arrow head width

System.out.println("Enter arrow base height: ");

arrowBaseHeight = scnr.nextInt(); // scans and reads the input as int

System.out.println("Enter arrow base width: ");

arrowBaseWidth = scnr.nextInt();

/* while loop to continue asking user for an arrow head width until the value entered is greater than the value of arrow base width */

while (arrowHeadWidth <= arrowBaseWidth) {

    System.out.println("Enter arrow head width: ");

    arrowHeadWidth = scnr.nextInt(); }

//start of the nested loop

//outer loop iterates a number of times equal to the height of the arrow base

 for (int i = 0; i < arrowBaseHeight; i++) {

//inner loop prints the stars asterisks

      for (int j = 0; j <arrowBaseWidth; j++) {

          System.out.print("*");        } //displays stars

          System.out.println();          }

//temporary variable to hold arrowhead width value

int k = arrowHeadWidth;

//outer loop to iterate no of times equal to the height of the arrow head

for (int i = 1; i <= arrowHeadWidth; i++)

{     for(int j = k; j > 0; j--)     {//inner loop to print stars

       System.out.print("*");    } //displays stars

   k = k - 1;

   System.out.println(); } } } // continues to add more asterisks for new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.

The loop is used to output an arrow base of height arrowBaseHeight. So point (1) is satisfied.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow. So (2) is satisfied.

A temporary variable k is used to hold the original value of arrowHeadWidth so that it keeps safe when modification is done.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head. So (3) is satisfied.

The value of temporary variable k is decreased by 1 so the next time it enters  the nested for loop it will be one asterisk lesser.

The screenshot of output is attached.

3 0
2 years ago
What does the following program segment do? Declare Count As Integer Declare Sum As Integer Set Sum = 0 For (Count = 1; Count &l
Troyanec [42]

1225

<u>Explanation:</u>

This segment helps initialize sum as 0. The for loop is used to increment with every execution and it is added to the sum. The loop runs 49 times and every time the count is added to the sum. In short it is the sum of first 49 natural numbers i.e 1+2+3+......+49.

6 0
2 years ago
The best approach to keeping your car in safe working order is to
Soloha48 [4]

Answer:

Explanation:

Your car's owner's manual will provide a maintenance schedule designed to keep your brakes in good condition. Following it is the easiest way to avoid expense repairs and the potential for catastrophic brake failure. But at the very least, you should have your brakes inspected every year.

3 0
2 years ago
Read 2 more answers
Consider a 1.80-m-tall man standing vertically in water and completely submerged in a pool. Determine the difference between the
defon

Answer:

17.658 kPa

Explanation:

The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.

P = \frac{weight}{base}

Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:

weight = \delta * v * g

Meanwhile, the volume of a column is the area of the base multiplied by the height:

V = base * h

Replacing:

P = \frac{\delta * base * h * g}{base}

The base cancels out, so:

P = \delta * h * g

The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.

If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:

\Delta P = \rho * g * (h1 - h2)

We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So:

\Delta P = 9.81 \frac{m}{s^{2} } * 1000 \frac{kg}{m^3} * 1.8 m = 17658 Pa = 17.658 kPa

4 0
2 years ago
A can of engine oil with a length of 150 mm and a diameter of 100 mm is placed vertically in the trunk of a car. On a hot summer
igomit [66]

Answer:

6.6516 W

Explanation:

The film temperature is given as the average of the two temperatures, hence (43 + 17)/2 = 30°C.

8 0
2 years ago
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