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2 years ago

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(a) Two point charges totaling 8.00 μC exert a repulsive force of 0.150 N on one another when separated by 0.500 m. What is the

charge on each? (b) What is the charge on each if the force is attractive?

2 answers:

Mrrafil [7]2 years ago

8 0

Answer:

3x10-7C

Explanation: Use Coulombs Law. Find q2 and derive the equation. Make sure to convert micro to decimals for accurate results

Anastaziya [24]2 years ago

7 0

3 is jxhuneuxndnzixbf

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An air-track cart with mass m1=0.28kg and initial speed v0=0.75m/s collides with and sticks to a second cart that is at rest ini

arsen [322]

Kinetic energy is calculated through the equation,

KE = 0.5mv²

At initial conditions,

m₁: KE = 0.5(0.28 kg)(0.75 m/s)² = 0.07875 J

m₂ : KE = 0.5(0.45 kg)(0 m/s)² = 0 J

Due to the momentum balance,

m₁v₁ + m₂v₂ = (m₁ + m₂)(V)

Substituting the known values,

(0.29 kg)(0.75 m/s) + (0.43 kg)(0 m/s) = (0.28 kg + 0.43 kg)(V)

V = 0.2977 m/s

The kinetic energy is,
KE = (0.5)(0.28 kg + 0.43 kg)(0.2977 m/s)²
KE = 0.03146 J

The difference between the kinetic energies is 0.0473 J.

7 0

2 years ago

Based on the free-body diagram, the net force acting on this wheelbarrow is {blank} N.

Semenov [28]

Answer:

diagram?

Explanation:

5 0

2 years ago

Read 2 more answers

When numbers are very small or very large, it is convenient to either express the value in scientific notation and/or by using a

Oxana [17]

Answer:

5 mg, $5\cdot 10^{-3}g$

Explanation:

First of all, let's rewrite the mass in grams using scientific notation.

we have:

m = 0.005 g

To rewrite it in scientific notation, we must count by how many digits we have to move the dot on the right - in this case three. So in scientific notation is

$m=5\cdot 10^{-3}g$

If we want to convert into milligrams, we must remind that

1 g = 1000 mg

So we can use the proportion

$1 g : 1000 mg = 0.005 g : x$

and we find

$x=\frac{(1000 mg)(0.005 g)}{1 g}=5 mg$

4 0

2 years ago

If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem

Jlenok [28]

Remain the same

Explanation:

If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.

Work done is the force applied to move a body through a distance.

Work done = F x d

where F is the applied force

d is the distance moved

Now;

if:

f = 2f

d = $\frac{1}{2}$ d

Input the parameter:

Work done = fxd = 2f x $\frac{1}{2}$ d = fd

The work done will still remain the same

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

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2 years ago

Two particles collide and stick together. If no external forces act on the two particles, which of the following is correct for

Semmy [17]

Answer:

c. $\Delta p$ =0 and $\Delta k$

Explanation:

We are given that two particles collide and stick together.

If there is no external force act on the two particles then ,it is inelastic collision.

Inelastic collision: There is some loss of kinetic energy but the momentum is conserved.

According to law of conservation of momentum

Initial momentum=Final momentum

Change in momentum=Final momentum-Initial momentum=0

Change in momentum= $\Delta p=0$

Initial kinetic energy is greater than final kinetic energy.

Change in kinetic energy=Final kinetic energy-kinetic energy=- negative

$\Delta k$

Hence, option c is true.

c. $\Delta p$ =0 and $\Delta k$

4 0

2 years ago