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Anastasy [175]
1 year ago
15

Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s

uits are red. Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).
Mathematics
2 answers:
lakkis [162]1 year ago
8 0

Answer:

<u>P (E1) = 1/2 or 50%</u>

<u>P (E2) = 3/13 or 23%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2.  Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

Lady bird [3.3K]1 year ago
6 0

Answer:

outcomes of E1 = [1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36]

outcomes of E2 = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35]

Step-by-step explanation:

PLATO

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There are 11 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with
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Step-by-step explanation:

a) 7!

If there are no restrictions, answer is 7! as it is the permutation of all animals.

b) 4! x 3!

As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among  themselves and the order of the dogs among themselves. There are 4! permutations of the cats and 3! permutations of the dogs, so there are a total of 4! x 3! possible arrangements of the suites.

c) 3! x 5!

There are 3! possible arrangements of  the dogs among themselves. Now, if we consider the dogs as  one ”object” together, then we can think of arranging the 4 cats  together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.

d) 2 x 4! x 3!

As required that all the cats must be together and all the dogs must be together, either the cats are all  before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e.  2 x 4! x 3!

3 0
2 years ago
I need a answer quick!!!!<br> Find 1/10 of 1/100 of a meter
Tema [17]
1/10= .1 of a meter
1/10 of 1/100= .001 of a meter
3 0
1 year ago
Within the United States, approximately 11.25% of the population is left-handed. Of the males, 12.6% are left-handed, compared t
GuDViN [60]

Answer:

There is a 45.05% probability that the selected person is a right-handed female.

Step-by-step explanation:

We have these following probabilities

A 50% probability that a person is a male

A 50% probability that a person is a female.

A 12.6% probability that a male is left-handed.

A 9.9% probability that a female is left-handed.

If a person is selected at random, to find the probability that the selected person is a right-handed female, one would compute:

50% are female.

9.9% of the females are left-handed, so 100-9.9 = 90.1% of the females are right handed.

So

P = 0.5*0.901 = 0.4505

There is a 45.05% probability that the selected person is a right-handed female.

3 0
2 years ago
A boat travels at constant speed. After 20 minutes the boat had traveled 2.5 miles. How long does it take the boat to reach the
schepotkina [342]

120 minutes

Step by step:

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7 0
2 years ago
If a piece of rope cost 20 cents per 2 feet, how many feet can you buy for 30 dollars?
katrin2010 [14]

Answer: 300\ feet

Step-by-step explanation:

Let be "x" the lenght in feet  of rope that you can buy with 30 dollars.

According to the information provided in the exercise, you can buy a piece of rope of 2 feet with 20 cents.

Remember that 20\ cents=0.2\ dollars

Knowing this, you can write the following proportion:

\frac{0.2}{2}=\frac{30}{x}

FInally, solving for "x", you get this result:

\frac{0.2}{2}=\frac{30}{x}\\\\x(\frac{0.2}{2})=30\\\\x=(30)(\frac{2}{0.20})\\\\x=300

6 0
2 years ago
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