Suppose that you're facing a straight current-carrying conductor, and the current is flowing toward you. The lines of magnetic f
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Answer:
Radius of the solenoid is 0.93 meters.
Explanation:
It is given that,
The magnetic field strength within the solenoid is given by the equation,
, t is time in seconds
The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m
The electric field due to changing magnetic field is given by :
x is the distance from the axis of the solenoid
, r is the radius of the solenoid
r = 0.93 meters
So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.
(a) The intensity of the electromagnetic wave is related to the amplitude of the electric field by
where
I is the intensity
c is the speed of light
is the electric permittivity
E is the amplitude of the electric field
By substituting the numbers of the problem and re-arranging the equation, we can find E:
Now that we have the intensity of the electric field, we can calculate the electric force on the charge:
(b) We can calculate the amplitude of the magnetic field starting from the amplitude of the electric field:
The magnetic force is given by
where v is the particle's speed, B the magnetic field intensity and
the angle between B and v.
In this case the charge is stationary, so v=0, and so the magnetic force is zero: F=0.
(c) The electric force has not changed compared to point (a), because it does not depend on the speed of the particle, so we have again F=0.046 N.
(d) This time, the particle is moving with speed
, in a direction perpendicular to the magnetic field (so, the angle 
is 
), and so by using the intensity of the magnetic field we found in point (b), we can calculate the magnetic force on the particle:
where
I is the intensity
c is the speed of light
E is the amplitude of the electric field
By substituting the numbers of the problem and re-arranging the equation, we can find E:
Now that we have the intensity of the electric field, we can calculate the electric force on the charge:
(b) We can calculate the amplitude of the magnetic field starting from the amplitude of the electric field:
The magnetic force is given by
where v is the particle's speed, B the magnetic field intensity and
In this case the charge is stationary, so v=0, and so the magnetic force is zero: F=0.
(c) The electric force has not changed compared to point (a), because it does not depend on the speed of the particle, so we have again F=0.046 N.
(d) This time, the particle is moving with speed