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Stells [14]
2 years ago
7

A bicycle factory installs about 400 tires per day. Tires are installed Monday through Friday for 8 hours per day. The manager o

f the factory estimates the number of properly installed tires per week using the process below.
In the first hour of work on Monday, 49 out of 50 tires were properly installed.

So, there were about 8(49) = 392 properly installed tires on Monday.

Considering 5 working days per week, 5(392) = 1,960 is the number of tires properly installed in one week.

Which best explains the validity of the results?
Mathematics
2 answers:
lions [1.4K]2 years ago
8 0

Answer:

The results are likely invalid because it is unlikely that the tires installed in one hour on Monday will represent the entire population of tires.

Step-by-step explanation:

Out of 8 hours, do you really think one hour will represent it all?

This is why the resutls are likely invalid ( also I took the quiz )

Answer: The results are likely invalid because it is unlikely that the tires installed in one hour on Monday will represent the entire population of tires.

Snezhnost [94]2 years ago
5 0

Answer:

The results are likely invalid because it is unlikely that the tires installed in one hour on Monday will represent the entire population of tires.

Step-by-step explanation:

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Two similar cones have heights of 9 cm and 4 cm. Find the ratio of their volumes
Rudik [331]

Answer:

The ratio of their volumes is:     \frac{729}{64}

Step-by-step explanation:

If the cones are similar, then the ratio of their heights should equal the ratio of their radiuses. If we call R the radius of the larger cone (the one of height 9 cm) and r the radius of the smaller cone (the one of height 4 cm), then the following proportion should be verified:

\frac{R}{r} =\frac{9}{4} \\R=\frac{9\,r}{4}

where we have solved for "R" in terms of "r".

Now we input this information in the formula for the volume (V) of the largest cone, and for the volume (v) of the smaller cone, recalling that the volume of a cone is the product of the area of the cone's circular base (\pi *\,radius^2).

v=\frac{\pi\,r^2\,4\,}{3} =\pi r^2\,\frac{4}{3} \\V=\frac{\pi\,R^2\,9}{3}=\frac{\pi\,(\frac{9\,r}{4} )^2\,9}{3}=\frac{\pi\,r^2\,729}{16*3}=\pi r^2\,\frac{243}{16}

So now the ratio of their volumes (V/v) can be obtained:

\frac{V}{v} =\frac{\frac{243}{16}}{\frac{4}{3}}  =\frac{729}{64}

6 0
2 years ago
Quinn returned home one summer's day to find it sweat-inducingly hot! He turned the air conditioner on and fell asleep. The room
Alenkasestr [34]

Answer:

f(x)=-0.5x+40

Step-by-step explanation:

To solve this problem, we need to find the linear function. We know that the constant rate of change is -0.5° Celsius per minute. Also, after 60 minutes the temperature was 10° Celsius. So, we have a one point and the slope of the linear function, let's use the point-slope formula

y-y_{1} =m(x-x_{1} )\\y-10=-0.5(x-60)\\y=-0.5x+30+10\\y=-0.5x+40

Where the y-intercept is at (0, 40).

Now, we have two points to graph the relation between minutes and Celsius degrees.

Therefore, the room's temperature as a function of time is

f(x)=-0.5x+40

Its graph is attached.

5 0
2 years ago
The mass of a colony of bacteria, in grams, is modeled by the function P given by P(t)=2+5tan^−1.(t/2), where t is measured in d
ira [324]

Answer:

1.21 g/day

Step-by-step explanation:

We are given that

The mass of a colony of bacteria (in (grams) is given by

P(t)=2+5tan^{-1}(\frac{t}{2})

Where t=Time(in days)

Differentiate w.r.t t

P'(t)=5(\frac{1}{1+\frac{t^2}{4}}\times \frac{1}{2})

By using the formula \frac{d(tan^{-1}(x)}{dx}=\frac{1}{1+x^2}

P'(t)=\frac{5}{2}(\frac{4}{4+t^2})

P'(t)=\frac{10}{4+t^2}

We are given P(t)=6

Substitute the value

6=2+5tan^{-1}(\frac{t}{2})

5tan^{-1}(\frac{t}{2})=6-2=4

tan^}{-1}(\frac{t}{2})=\frac{4}{5}

\frac{t}{2}=tan(\frac{4}{5})

t=2tan(\frac{4}{5})

Substitute the value of t

P'(2tan\frac{4}{5})=\frac{10}{4+4tan^2(\frac{4}{5})}

P'(2tan\frac{4}{5})=\frac{10}{4}\times \frac{1}{1+tan^2(\frac{4}{5})}

We know that 1+tan^2\theta=sec^2\theta

Using the formula

P'(2tan(\frac{4}{5})=\frac{5}{2}\times \frac{1}{sec^2(\frac{4}{5})}

P'(2tan\frac{4}{5})=\frac{5}{2}\times cos^2(\frac{4}{5})

By using cos^2x=\frac{1}{sec^2x}

P'(2tan\frac{4}{5})=\frac{5}{2}\times (0.696)^2=1.21g/day

Hence,the instantaneous rate of change of the mass of the colony=1.21g/day

7 0
2 years ago
Read 2 more answers
The expression shown can be used to calculate the amount of money in dollars a grocery store customer should receive in change w
Readme [11.4K]

Answer:

The change received by the customer is $7.

Step-by-step explanation:

First, write the given expression for the change when paying with $50.

50 - ( 14 + 12 + 2 ( 5 ) + 2 ( 2 ) + 3 )

Evaluate the parentheses:

50-(26+10+4+3)

Now add the numbers inside the parentheses.

50-43

Subtract the numbers.

7

Hence, the change received by the customer is $7.

4 0
2 years ago
The following is an incomplete paragraph proving that the opposite sides of parallelogram ABCD are congruent:
OverLord2011 [107]
<span>D) Angles BAC and DCA are congruent by the Alternate Interior Angles Theorem.</span>
8 0
2 years ago
Read 2 more answers
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