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mojhsa [17]
2 years ago
5

Horatio is solving the equation Negative three-fourths + two-fifths x = StartFraction 7 Over 20 EndFraction x minus one-half. Wh

ich equations represent possible ways to begin solving for x? Check all that apply. Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth Two-fifths x = StartFraction 7 Over 20 EndFraction x + five-fourths Negative three-fourths = negative StartFraction 1 Over 20 EndFraction x minus one-half Negative three-fourths = three-fourths x minus one-half Negative three-fourths + StartFraction 1 Over 20 EndFraction x = negative one-half
Mathematics
2 answers:
galben [10]2 years ago
7 0

Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth

Step-by-step explanation:

allsm [11]2 years ago
5 0

Answer:

Option "Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth" is correct

That is \frac{2}{5}x=\frac{7}{20}x+\frac{1}{4} is the equation represents the possible ways to begin for solving x

Step-by-step explanation:

Horatio is solving the equation Negative three-fourths + two-fifths x = StartFraction 7 Over 20 EndFraction x minus one-half

It can be written as below

-\frac{3}{4}+\frac{2}{5}x=\frac{7}{20}x-\frac{1}{2}

Now Horatio soved the above equation :

-\frac{3}{4}+\frac{2}{5}x=\frac{7}{20}x-\frac{1}{2}

\frac{2}{5}x=\frac{7}{20}x-\frac{1}{2}+\frac{3}{4}

\frac{2}{5}x=\frac{7}{20}x+(\frac{-2+3}{4})

\frac{2}{5}x=\frac{7}{20}x+\frac{1}{4} is the equation represents the possible ways to begin for solving x

Therefore it can be represented by "Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth"

Therefore option Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth is correct

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Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa
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Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

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So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

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The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

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c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

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After turning to south ferry remains in radar for 6.7 min

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