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lina2011 [118]
2 years ago
13

- A jackrabbit's powerful legs are an example of a

Chemistry
2 answers:
dusya [7]2 years ago
8 0

Answer:

I think it is b.

Explanation:

vlabodo [156]2 years ago
4 0

It should be structural adaption, so A

You might be interested in
why does every human measurement have uncertainty associated with it? Why must we manage the uncertainty during calculations?
dimulka [17.4K]
Because there are many numbers of the human measurement . we must manage the uncertainly doing calculations because we can know what we are calculating.
3 0
2 years ago
Convert 2.0 M of Phenobarbital sodium (MW: 254 g/mole) solution in water into % w/v and ratio strengths.
Travka [436]

Answer:

The concentration is 50,8 % w/v and radio strengths = 1,96.

Explanation:

Phenobarbital sodium is a medication that could treat insomnia, for example.

2,0 M of Phenobarbital sodium means 2 moles in 1L.

The concentration units in this case are %w/v that means 1g in 100 mL and ratio strengths that means  1g in <em>r</em> mL. Thus, 2 moles must be converted in grams with molar weight -254 g/mole- and liters to mililiters -1 L are 1000mL-. So:

2 moles × \frac{254 g}{1 mole}= 508 g of Phenobarbital sodium.

1 L ×\frac{1000 mL}{ 1 L} = 1000 mL of solution

Thus, % w/v is:

\frac{508 g}{1000 mL} × 100 = 50,8 % w/v

And radio strengths:

\frac{1000 mL}{508 g}  = 1,96. Thus, you have 1 g in 1,96 mL

I hope it helps!

5 0
2 years ago
Find the molarity of 186.55 g of sugar (C12H22O11) in 250. mL of water.
Anna [14]

Answer:

The molarity of this sugar solution in water is 2.18 M

Explanation:

Step 1: Data given

Mass of sugar (C12H22O11) = 186.55 grams

Molar mass of C12H22O11 = 342.3 g/mol

Volume of water = 250.0 mL = 0.250 L

Step 2: Calculate moles sugar

Moles sugar = mass sugar / molar mass sugar

Moles sugar = 186.55 grams / 342.3 g/mol

Moles sugar = 0.545 moles

Step 3: Calculate molarity of the sugar solution

Molarity = moles sugar / volume of water

Molarity = 0.545 moles / 0.250 L

Molarity = 2.18 MThe molarity of this sugar solution in water is 2.18 M

6 0
2 years ago
The Lewis structure for CO2 has a central The Lewis structure for C O 2 has a central blank atom attached to blank atoms.
kirza4 [7]

Answer:

See the explanation

Explanation:

1) The Lewis structure for  CO_2 has a central Carbon<em> </em>atom attached to Oxygen atoms.

In the CO_2  we will have a structure:  O=C=O the <u>central atom</u> "carbon" we will have <u>2 sigma bonds and 2 pi bonds</u>, therefore, we have an <u>Sp hybridization</u>. For O we have <u>1 pi and 1 sigma bond</u>, therefore, we have an <u>Sp2 hybridization</u>.

2) These atoms are held together by <u>double bonds.</u>

<u></u>

Again in the structure of CO_2: O=C=O we only have double bonds.

3. Carbon dioxide has a Carbon dioxide has a <u>Linear</u> electron geometry.

Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.

4. The carbon atom is <u>Sp</u> hybridized.

We will have for carbon 2 pi bonds, so we will have an <u>Sp</u> hybridization.

5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.

(See figures)

Figure 1: Carbon hybridization

Figure 2: Oxygen hybridization

6 0
2 years ago
To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute
julia-pushkina [17]

Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molar concentration of undiluted cognac = ?

M_2 = molar concentration of diluted cognac = 0.0844 M

V_1 =  volume of undiluted cognac = 5.00 mL = 0.005 L

V_2 = volume of diluted cognac = 0.500 L

Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

M_1\times 0.005L=0.0844M\times 0.500L

M_1=8.44M

Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M

4 0
2 years ago
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