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svet-max [94.6K]
2 years ago
5

How many even numbers are greater than 202 and less than 405?

Mathematics
2 answers:
Aleks04 [339]2 years ago
5 0

Answer:

203 numbers are between 202 and 405

Step-by-step explanation:

405 - 202 = 203

Harlamova29_29 [7]2 years ago
4 0
It would be 404 as it say less than and 203 as it says greater then 404 - 203 which would equal 201 and then you would have to find out how many even numbers are in that 201 numbers.
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Equation::
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Simplify x+2/x^2-6x-16 divided by 1/9x<br>a. 10x/x+4<br>b. x+4<br>c. 10x^2(x+2)/x+6<br>d. 9x/x-8
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2 years ago
Norma Jean makes $25 per hour. She works 35 hours per week. She gets a commission of 15% on her total sales. How much should Nor
TEA [102]

Answer:

$24166.67

Step-by-step explanation:

$25 per hour and works 35 hours per week

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6 0
2 years ago
Read 2 more answers
The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
Dahasolnce [82]

Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

4 0
2 years ago
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