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2 years ago

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On Saturday, Mark sold 2 7/8 gallons of lemonade. On the same day, Regan sold 2/3 as much lemonade as Mark. How much lemonade, i

n gallons did Regan sell?

1 answer:

MAXImum [283]2 years ago

6 0

2 7/8= 2/3L
Divide both sides by 2/3 and get 4.31 or 4 5/16
Hope this helps!!

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11/12−6/1q+6/5q−3/1, Combine like terms to create an equivalent expression.

Nikolay [14]

Answer: $-\frac{25}{12} -\frac{24q}{5}$

Step-by-step explanation:

$\frac{11}{12} -\frac{6}{1} q+\frac{6}{5}q-\frac{3}{1}$

$\frac{11}{12} -6q+ \frac{6q}{5} -\frac{3}{1}$

$\frac{11}{12}-6q \frac{6q}{5} -3$

$(\frac{11}{12} -3)+(-6q+\frac{6q}{5} )$

$-\frac{25}{12}- \frac{24q}{5}$

Simplify three times, collect like terms and simplify again, how to collect like terms see their differences and then put them into groups, for example I put all the numbers without variables on one side and all the numbers with variables on another.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

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2 years ago

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What is 1.532 rounded to the nearest hundredth

Anni [7]

Answer:

1.53 would be the answer

Step-by-step explanation:

If you are rounding to the nearest hundredth you are rounding to the 2nd decimal place. Since the next number is under 5, we would just drop it.

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2 years ago

What is 119,000,003 in expanded form

stira [4]

100,000,000+10,000,000+9,000,000+3

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2 years ago

F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 x 2

34kurt

Answer:

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

$g(f(x)) = 3x^4 + 18x^2 + 18$

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

$f(x) = 3x^2 + 9$

$g(x) = \dfrac{1}{3}x^2 - 9$

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

$f(x) = 3x^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9$

$f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9$

Expand Brackets

$f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9$

$f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9$

$f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252$

Calculating g(f(x))

$g(x) = \dfrac{1}{3}x^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9$

$g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9$

$g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9$

Expand Brackets

$g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9$

$g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9$

$g(f(x)) = 3x^4 + 18x^2 + 18$

Checking for inverse functions

$f(x) = 3x^2 + 9$

Represent f(x) with y

$y = 3x^2 + 9$

Swap positions of x and y

$x = 3y^2 + 9$

Subtract 9 from both sides

$x - 9 = 3y^2 + 9 - 9$

$x - 9 = 3y^2$

$3y^2 = x - 9$

Divide through by 3

$\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}$

$y^2 = \frac{x}{3} - 3$

Take square root of both sides

$\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}$

$y = \sqrt{\frac{x}{3} - 3}$

Represent y with g(x)

$g(x) = \sqrt{\frac{x}{3} - 3}$

Note that the resulting value of g(x) is not the same as $g(x) = \dfrac{1}{3}x^2 - 9$

<em>Hence, f(x) and g(x) and not inverse functions</em>

4 0

2 years ago

(01.02 LC)Simplify 9 − (−4).

levacccp [35]

Answer:

13

Step-by-step explanation:

When we subtract a negative, it is like adding

9 - -4

9 +4

13

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2 years ago

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