<u>Answer:</u> The particle released in the given reaction is one alpha particle
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
For the given fission reaction:
Total mass on reactant side = total mass on product side
222 = A + 218
A = 4
Total atomic number on reactant side = total atomic number on product side
86 = Z + 84
Z = 2
The isotopic symbol of unknown element is 
. Another name of helium atom is alpha particle.
Hence, the particle released in the given reaction is one alpha particle
Electrochemical cell representation for above reaction is,
Br-/Br2//I2/I-
Reaction at Anode: Br2 + 2e- → 2Br- (1)
Reaction at Cathode: 2I- → I2 + 2e- (2)
Standard reduction potential for Reaction 1 = Ered(anode) = 1.066 v
Standard reduction potential for Reaction 2 = Ered(cathode) = 0.535 v
Eo cell = Ered(cathode) - Ered(anode)
= 0.535 - 1.066
= -0.531v
Now, we know that ΔGo = -nF (Eo cell) ..............(3)
Also, ΔGo = RTln(K) ..........(4)
Equation 3 and 4 we get,
ln (K) = nF (Eo cell) / RT
= 2 X 96500 X (-0.531)/ (8.314 X 298)
∴ K = 1.085 X 10^-18.
The correct steps in lighting a Bunsen burner would be as follows: First, clean the area. Get rid of any flammable substances near the burner. Second, close the air supply Third, turn on the gas supply to the burner. Fourth, use a lighter to light the flame. Fifth, adjust the flow of air to control the flame.
0.17 M is the is the molal concentration of this solution
Explanation:
Data given:
freezing point of glucose solution = -0.325 degree celsius
molal concentration of the solution =?
solution is of glucose=?
atomic mass of glucose = 180.01 grams/mole
freezing point of glucose = 146 degrees
freezing point of water = 0 degrees
Kf of glucose = 1.86 °C
ΔT = (freezing point of solvent) - (freezing point of solution)
ΔT = 0.325 degree celsius
molality =?
ΔT = Kfm
rearranging the equation:
m = 
m= 0.17 M
molal concentration of the glucose solution is 0.17 M
= change, (pretend it’s a triangle)
Joules = M x T x C
M = mass (looking for M in this problem)
T =change in temperature(42C-23C=19C)
C= specific heat capacity
1,160 = (M)(19C)(1.716)
1,160= 32.604M
1,160/32.604M = 35.58g
M= 35.58g
Your answer is C
