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blagie [28]
2 years ago
9

A leather ball has a diameter of 28.4 cm. Which is the area of the piece of leather used on the surface of the ball?

Mathematics
2 answers:
MrRissso [65]2 years ago
7 0

Answer:

has the same diameter as the sphere, and height equal to its diameter. ... The surfce area of a soccer ball is 250 square inches. ... An official basketball has a radius of 12.5 cm and ... much leather is required to cover 12 official.

Step-by-step explanation:

Varvara68 [4.7K]2 years ago
5 0

Answer:

2534 cm^2 to the nearest whole number.

Step-by-step explanation:

The ball is a sphere whose surface are is 4 pi r^2

The radius r = 1/2 diameter = 1/2 * 28.4

= 14.2 cm.

The required area = 4 * pi * 14.2^2

= 2533.88 cm^2

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Rhombus LMNO is shown with its diagonals. The length of LN is 28 centimeters. What is the length of LP? 7 cm 9 cm 14 cm 21 cm
vampirchik [111]
LP= 1/2 * 28 = 14 Answer C.
7 0
2 years ago
Read 2 more answers
Lorie is using long division to find the quotient of x^3 + 6x^2 + 5 and x^2 + x -1, as shown at the bottom of this question.
meriva

Answer:

Option (B)

Step-by-step explanation:

x² + x - 1) x³ + 6x² + 0x + 5 ( x + 5

           - (<u>x³ +   x²  -  x</u>)

                      5x² + x + 5

                    -(<u>5x² + 5x - 5)</u>

                             -4x + 10

Result : x+5+\frac{-4x+10}{(x^{2}+x-1)}

By the comparing the result with the Lorie's solution,

She made a mistake in the last step in which she combined the constant incorrectly.

Therefore, Option (B) will be the answer.

7 0
2 years ago
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
Vadim26 [7]

Answer:

B) 28.53 unit²

Step-by-step explanation:

The diagonal AD divides the quadrilateral in two triangles:

  1. Triangle ABD
  2. Triangle ACD

Area of Quadrilateral will be equal to the sum of Areas of both triangles.

i.e.

Area of ABCD = Area of ABD + Area of ACD

Area of Triangle ABD:

Area of a triangle is given as:

Area = \frac{1}{2} \times base \times height

Base = AB = 2.89

Height = AD = 8.6

Using these values, we get:

Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43

Thus, Area of Triangle ABD is 12.43 square units

Area of Triangle ACD:

Base = AC = 4.3

Height = CD = 7.58

Using the values in formula of area, we get:

Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30

Thus, Area of Triangle ACD is 16.30 square units

Area of Quadrilateral ABCD:

The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²

None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²

7 0
2 years ago
Work out ( 8x10 -3) x(2x10 -4) standard form
zheka24 [161]

Answer:  1232

Step-by-step explanation:  ( 8x10 -3) x(2x10 -4)  

( 8x10 -3) = 77

(2x10 -4) = 16

77 x 16 = 1232

Answer = 1232

4 0
2 years ago
Which equation accurately represents this statement? Select three options.
atroni [7]

Complete question:

Which equation accurately represents this statement? Check all that apply.

Negative 3 less than 4.9 times a number, x, is the same as 12.8

A: -3-4.9x=12.8

B: 4.9x-(-3)=12.8

C: 3+4.9x=12.8

D: (4.9-3)x=12.8

E:  12.8=4.9x+3

Answer:

B: 4.9x-(-3)=12.8

C: 3+4.9x=12.8

E:  12.8=4.9x+3

Step-by-step explanation:

The word equation can be expressed mathematically as follows

negative 3  → -3

less than 4.9 times a number , x →  4.9 x - (-3)

is same as 12.8  → 4.9 x - (-3) = 12.8

The equation can be expressed as

4.9 x - (-3) = 12.8

when you open the bracket, you multiply  -3 time  - 1 . MInus times minus is equals to plus. so you get

4.9 x + 3 = 12.8

12.8 = 4.9x+3

3 0
2 years ago
Read 2 more answers
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