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1 year ago

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nora and hana are tiling two floors in their houses. by noon, nora had laid 3/4 of her tiles. hana had laid 1/2 of her tiles. th

ey laid the same number of tiles. how many tiles might each person have started with?

1 answer:

kondaur [170]1 year ago

5 0

Nora could started with 16 and Hana with 24

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Landon babysits and works part time at tge water park over the summer. onw week, he babysat for 3 hours and worked at the water

Tems11 [23]

B = hourly rate for babysitting and w = hourly rate for working at water park

3b + 10w = 109...multiply by -8
8b + 12w = 177...multiply by 3
----------------------
-24b - 80w = - 872 (result of multiplying by -8)
24b + 36w = 531 (result of multiplying by 3)
---------------------add
- 44w = - 341
w = -341/-44
w = 7.75 <=== hourly rate for working at water park

3b + 10w = 109
3b + 10(7.75) = 109
3b + 77.50 = 109
3b = 109 - 77.50
3b = 31.50
b = 31.50/3
b = 10.50 <== hourly rate for babysitting

8 0

1 year ago

Read 2 more answers

Test 24,515 for divisibility by 2, 3, 5, 9, or 10.

lord [1]

Answer:

D

Step-by-step explanation:

1. When a number is divisible by 2 it must end with even digit 0, 2, 4, 6 or 8.

So the number 24,515 is not divisible by 2.

2. When a number is divisible by 5 it must end with digit 0, or 5.

The number 24,515 ends with 5 so it is divisible by 5.

3. When a number is divisible by 3, the sum of all digits must be divisible by 3.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 3, so the number 24,515 is not divisible by 3.

4. When a number is divisible by 9, the sum of all digits must be divisible by 9.

The sum of all digits of the number 24,515 is 2+4+5+1+5=17. 17 is not divisible by 9, so the number 24,515 is not divisible by 9.

5. When a number is divisible by 10 it must end with digit 0.

The number 24,515 ends with 5 so it is not divisible by 10.

8 0

1 year ago

People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the

Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0

2 years ago

What is 13/56 + 5/7=

Darya [45]

<span>The question is asking us to calculate : 13/56 + 5/7. To do this we have first to find the common denominator for these fractions. We know that 56 = 7 * 8, so the common denominator is 56. Then we will multiply the numerator and the denominator of the second fraction by 8. 5/7 * 8/8 = 40/56. Finally we will add : 13/56 + 40/56 = 53/56 and that is the final answer, which can not be simplified. Answer: 53/56</span>

7 0

1 year ago

A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid

mario62 [17]

Answer:

The area of the shaded region is $329.87\ cm^2$

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

so

$A=\pi r_a^{2} -\pi r_b^{2}$

simplify

$A=\pi (r_a^{2} -r_b^{2})$

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

$r_a=11\ cm\\r_b=4\ cm$

substitute

$A=\pi (11^{2} -4^{2})$

$A=\pi (105)\ cm^2$

assume

$\pi=3.1416$

substitute

$A=(3.1416)(105)=329.87\ cm^2$

7 0

2 years ago