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lbvjy [14]
2 years ago
4

Calls are repeatedly placed to a busy phone line until a connect is achieved. Let c = connect and b = busy, select the correct s

ample space, S, below: A. S = {b, c} B. S = {bbbbbb, ...} C. S = {cb, cbb, cbbb, ...} D. S = {c, bc, bbc, bbbc, ...}
Mathematics
1 answer:
alina1380 [7]2 years ago
3 0

Answer:

(D)

Step-by-step explanation:

(A)

Let's have a look at the first sample space, the set

                                      S = \{b,c\}

As we can see, it consists of two elements. Element b implies that a call was made, but the line was busy, and the element c implies that the call was connected. However, this sample space doesn't correspond to the event in which the calls are repeatedly made until a connect is achieved. The element c is suitable, because it is possible that the line wasn't busy at the moment of calling, but the element  b implies that after receiving the busy signal, there were no further attempts to connect to the line.

(B)

The second sample space is

                                  S =\{bbbbbb, \ldots \}

It corresponds to the case in which after a few attempts to connect to the line, the person gave up. Therefore, it doesn't correspond to our problem.

(C)

The third sample space is

                                  S = \{ cb, cbb, cbbb, \ldots \}

It corresponds to the case in which after one successful attempt, the person tried again for a few more times, and also gave up before connecting again. Therefore, it doesn't correspond to our problem either.

(D)

The last sample space is

                              S = \{ c, bc, bbc, bbbc, \ldots\}

The first element corresponds to the case that the line wasn't busy in the first attempt. The second element, bc, corresponds to the case in which the line was busy in the first attempt but it wasn't in the second. The third is the one in which the line was busy for three attempts, but wasn't in the fourth, and so on. As we can see, the common thing about all this elements is that the there were no further attempts after a connection was achieved, which corresponds to our case. Therefore, this is the correct sample space.

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2 years ago
The menu price of a sandwich at a restaurant is $6. The purchase is subject to a 5% food tax, and you would like to leave a tip
Leya [2.2K]

Answer: See explanation

Step-by-step explanation:

Price of sandwich = $6

Food tax = 5% of $6

= 0.05 × $6

= $0.3

Tip = 20% of $6

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= $1.2

Total cost of meal:

= $6 + $0.3 + $1.2

= $7.5

3 0
2 years ago
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Assuming no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales b
alexira [117]

Answer:

Step-by-step explanation:

Given that we assume  no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.

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Here fixed cost = 3 million dollars

Sales - variable = contribution = 35%

35% should atleast meet the fixed cost

i.e. 35% = 3 million

100% = 8.57 million can be cost

Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs

So material and labor cost should be limited upto 5.57 million increase.

3 0
2 years ago
Exercise 6.12 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they canno
tensa zangetsu [6.8K]
<h2>Answer with explanation:</h2>

As per given , we have

\hat{p}=0.48   , n=331

Critical value for 90% Confidence interval : z_{\alpha/2}=1.645

a) Confidence interval :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

0.48\pm (1.645)\sqrt{\dfrac{0.48(1-0.48)}{331}}\\\\\approx 0.48\pm0.02746\\\\=(0.48-0.02746,\ 0.48+0.02746)\\\\=(0.45254,\ 0.50746)

Hence, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot a ord it : (0.45254,\ 0.50746)

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Formula for sample size : n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

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n=0.48(1-0.48)(\dfrac{1.645}{0.015})^2=3001.88373333\approx3002

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6 0
2 years ago
Z to the power of 2 =1
stiv31 [10]

That would be written as:

z^{2} = 1


And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

z = \sqrt{1} →we solve for \sqrt{1}

z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



Hope it helped,



BioTeacher101

3 0
2 years ago
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