consider the motion of con from top to bottom
Y = vertical displacement = 1000 m
a = acceleration due to gravity = 9.8 m/s²
v₀ = initial velocity at the top = 0 m/s
v = final velocity at the bottom = ?
using the kinematics equation
v² = v²₀ + 2 aY
v² = 0² + 2 (9.8) (1000)
v = 140 m/s
t = time taken to hit the ground
Using the equation
v = v₀ + at
140 = 0 + 9.8 t
t = 14.3 sec
Answer:
The magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Explanation:
The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.
The radial acceleration is given by;

where;
a is the angular acceleration and
r is the radius of the circular path

Determine time of the rotation;

Determine angular velocity
ω = at
ω = 1.6 x 0.707
ω = 1.131 rad/s
Now, determine the radial acceleration

The magnitude of total linear acceleration is given by;

Therefore, the magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Answer:
A wavelength is a measure of distance between two consecutive crests or trough. So , the unit of wavelength is same as unit of distance. I.e metre