Note that: (10x - 61) & (x + 10) are supplementary angles, and (10x-61) & (18y + 5) are vertical angles
10x - 61 + x + 10 = 180
Simplify
11x - 51 = 180
Isolate the x
11x - 51 (+51) = 180 (+51)
11x = 231
Divide 11 from both sides
11x/11 = 231/11
Divide
x = 21
180 = 18y + 5 + x + 10
180 = 18y + 5 + (21) + 10
Simplify
180 = 18y + 36
Subtract 36 from both sides
180 (-36) = 18y + 36 (-36)
144 = 18y
Divide 18 from both sides
144/18 = 18y/18
y = 144/18
y = 8
x = 21, y = 8 are your answers
hope this helps
Answer:
45
Step-by-step explanation:
2 digit number starts from 10 ends at 99
between 10 and 19 there is only one number whose tens digit is more than ones digit.
that is 10
between 20 and 29 there are two numbers
20 and 21
like the same
between 30 and 39 there are 3 numbers
10–19. 1
20–29. 2
30–39. 3
40–49. 4
50–59. 5
60–69. 6
70–79. 7
80–89. 8
99–99. 9
sum of first n natural numbers is n(n+1)/2
9(9+1)/2=45
Answer:
84%
Step-by-step explanation:
The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.
If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:


Answer:
x > 4/3
Step-by-step explanation:
The first inequality can be solved this way ...
3x -91 > -87
3x > 4 . . . . . . . add 91
x > 4/3 . . . . . . divide by 3
__
The second inequality has solution ...
21x -17 > 25
21x > 42 . . . . . . add 17
x > 2 . . . . . . . . . divide by 21
__
The solution set is the union of these overlapping solutions, so will be equal to the first solution:
x > 4/3
Answer:
i hope this helps
Step-by-step explanation:
The answer would be A, or "A box-and-whisker plot. The number line goes from 0 to 12, and the box ranges from 4 to 10. A line divides the box at 7.
Step-by-step explanation:
If you plot the data (2, 4, 6, 8, and 12) it looks something like the poor box-and-whisker plot below
⊕← | Ф | →⊕
|---|---|---|---|---|---|---|---|---|---|---|---|
0 1 2 3 4 5 6 7 8 9 10 11 12
Description A describes that exact box-and-whisker plot.