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lana66690 [7]
2 years ago
5

PLEASE HELP!! WILL GIVE BRAINLIEST FOR THE FIRST LEGIT ANSWER!!

Mathematics
1 answer:
algol132 years ago
6 0

The headings correctly complete the chart is X: Zygote fungi , Y: Club fungi , and Z: Sac fungi.

Option: D.

<u>Explanation:</u>

Zygote fungi : Zygote fungi are terrestrial and exist in decaying plants, animal material or soil. It reproduces asexually through sporangia(spore-producing enclosure) hyphae, which will be loosely organized or assorted into complex structures.

Club fungi : Club fungi can be found in the form of puffballs, mushrooms, and rusts. The spores are produced by sexual reproduction and the spores drip from its "gills" which is firmly packed hyphae.

Sac fungi: Sac fungi exist in freshwater, marine, and terrestrial environments. They are single-celled kinds that usually reproduce asexually during suitable conditions, and sexually during the harsh conditions.

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The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
2 years ago
Sasha runs at a constant speed of 3.8 meters per second for 1/2 hour.Then she walks at a constant rate of 1.5 meters per second
Arisa [49]

Answer:

Step-by-step explanation:

Distance covered = speed × time.

Sasha runs at a constant speed of 3.8 meters per second for 1/2 hour.

This means distance covered while running would be

3.8 × 1/2 = 1.9 meters

Then she walks at a constant rate of 1.5 meters per second for 1/2 hour. This means distance covered while walking would be

1.5 × 1/2 = 0.75 meters

Total distance that Sasha covered while running and walking in 60 minutes would be

1.9 + 0.75 = 2.65 meters

3 0
2 years ago
Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

8 0
2 years ago
sarah invests £9600 at a simple interest rate of 8% per year. Work out the value of the investment after 3 years
andre [41]

Answer:

the value of the investment after 3 years=  £11,904

Step-by-step explanation:

sarah invests £9600 at a simple interest rate of 8% per year

number of years = 3

Formula for simple interest

I = P*n* r

P is the initial amount invested= 9600

r is the rate of interest = 8% = 0.08

n = number of years = 3

Now we find interest using formula

I = 9600 * 0.08 * 3= 2304

Interest amount is 2,304

Now we add the interest with the initial amount to get the value of investment after 3 years

9600 + 2304= 11904

6 0
2 years ago
Which expression is equivalent to 144 Superscript three-halves? 216 1,728 RootIndex 3 StartRoot 12 EndRoot RootIndex 3 StartRoot
Afina-wow [57]

Question:

Which expression is equivalent to 144^(3/2)

Answer:

1728

Step-by-step explanation:

The options are not well presented. However, this is the solution to the question.

Given:

144^(3/2)

Required:

Find Equivalent.

We start my making use of the following law of logarithm.

A^(m/n) = (A^m)^1/n

So,

144^(3/2) = (144³)^½

Another law of indices is that

A^½ = √A

So,

144^(3/2) = (144³)^½ = √(144³)

144³ can be expanded as 144 * 144 * 144.

This gives

144^(3/2) = √(144 * 144 * 144)

The square root can then be splitted to

144^(3/2) = √144 * √144 * √144

144^(3/2) = 12 * 12 * 12

144^(3/2) = 1728.

Hence, the equivalent of 144^(3/2) is 1728

8 0
2 years ago
Read 2 more answers
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