Remmber
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
conver to improper
4 and 1/5=20/5+1/5=21/5
2 and 1/3=6/3+1/3=7/3
(21/5)/(7/3)=(21/5)(3/7)=63/35=9/5=1 and 4/5
Recall that
There are three cases to consider:
(1) When
, we have
and
, so
(2) When
and
, we get
and
, so
(3) When
, we have
and
, so
So
Answer:
Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.
Step-by-step explanation:
Alannah has two ribbons one length is 36cm and other is 45cm.
It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.
So, let's find greatest common factor for both 36 and 45.
Let's prime factor each number
36= 2*2*3*3
45= 3*3*5
So, GCF is product of common factors for both numbers.
GCF= 3*3 =9
So, longest possible length for each of the shorter lengths of ribbon is 9 cm.
Learn more about GCF in brainly.com/question/21612147.
So what I did was as $32.50 twice and got $65.00 and subtracted it with $212.50 and got $152.50. Hope i was helpful!
