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anygoal [31]
2 years ago
12

The density of mercury is 13.6 g/cm3. What is the mass in pounds of 1.0 gallons of mercury? (1 lb = 453.6 g; 1 gal = 3.785 L)

Chemistry
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

1.1 × 10² lb

Explanation:

First, we will convert 1.0 gallons to cm³ using the following relations.

  • 1 gal = 3.785 L
  • 1 L = 10³ mL
  • 1 mL = 1 cm³

1.0 gal.\frac{3.785L}{1gal} .\frac{10^{3}mL}{1L} .\frac{1cm^{3} }{1mL} =3.8\times 10^{3} cm^{3}

<em>The density (ρ) is equal to the quotient between the mass (m) and the volume (V).</em> The mass corresponding to 3.8 × 10³ cm³ is:

3.8 × 10³ cm³ × 13.6 g/cm³ = 5.2 × 10⁴ g

1 pound is equal to 453.6 grams. The pounds corresponding to 5.2 × 10⁴ grams are:

5.2 × 10⁴ g × (1 lb/453.6 g) = 1.1 × 10² lb

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Ammonia NH3 may react with oxygen to form nitrogen gas and water.4NH3 (aq) + 3O2 (g) \rightarrow 2 N2 (g) + 6H2O (l)If 2.15g of
bagirrra123 [75]

Answer:

NH3 is the limiting reactant

The % yield is 36.1 %

Explanation:

<u>Step 1: </u>Data given

Mass of NH3 = 2.15 grams

Mass of O2 = 3.23 grams

Molar mass of NH3 = 17.03 g/mol

Molar mass of O2 = 32 g/mol

volume of N2 produced = 0.550 L

Temperature = 295 K

Pressure = 1.00 atm

<u>Step 2:</u> The balanced equation:

4NH3 (aq) + 3O2 (g) → 2 N2 (g) + 6H2O (l)

<u>Step 3:</u> Calculate moles of NH3

Moles NH3 = Mass NH3 / Molar Mass NH3

Moles NH3 = 2.15 grams / 17.03 g/mol

Moles NH3 = 0.126 moles

<u>Step 4:</u> Calculate moles of O2

Moles O2 = 3.23 grams / 32 g/mol

Moles O2 = 0.101 moles

<u>Step 5: </u>Calculate the limiting reactant

For 4 moles NH3 consumed, we need 3 moles of O2 to produce, 2 moles of N2 and 6 moles of H2O

NH3 is the limiting reactant. It will completely be consumed ( 0.126 moles).

O2 is in excess, there will be 3/4 * 0.126 = 0.0945 moles consumed

There will remain 0.101 - 0.945 = 0.0065 moles of O2

<u>Step 6:</u> Calculate moles of N2

For 4 moles NH3 consumed, we need 3 moles of O2 to produce, 2 moles of N2 and 6 moles of H2O

For 4 moles NH3 , we'll have 2 moles of N2 produced

For 0.126 moles NH3 consumed, we'll have 0.063 moles of N2 produced.

<u>Step 7</u>: Calculate volume of N2 produced

p*V = n*R*T

⇒ with p = the pressure of the gas = 1.00 atm

⇒ with V = the volume = TO BE DETERMINED

⇒ with n = the number of moles N2 = 0.063 moles

⇒ with R = the gasconstant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 295

V = (nRT)/p

V = (0.063*0.08206*295)/1

V = 1.525 L = theoretical yield

<u>Step 8:</u> Calculate the % yield

% yield = actual yield / theoretical yield

% yield = (0.550 L / 1.525 L)*100%

% yield = 36.1 %

4 0
2 years ago
How many moles of copper are in 6,000,000 atoms of copper?
crimeas [40]

Answer: There will be 9.9632 × 10⁻¹⁸ moles of Copper in 6,000,000 atoms of Copper.

7 0
1 year ago
A. Consider four different samples: aqueous LiI, molten LiI, aqueous AgI, and molten AgI. Current run through each sample produc
Rudiy27

Answer:

Explanation:

At the cathode

In case of molten AgI

Silver  will be collected

In case of molten LiI

lithium will be collected

in case of aqueous LiI,

hydrogen gas will be collected as reduction potential of H⁺ is more than Li⁺

in case of aqueous AgI,

Silver will be obtained at cathode because reduction potential of silver is more than H⁺

At the Anode  

In case of molten NaBr  

Bromine   will be collected

In case of molten NaF

Fluorine  will be collected

in case of aqueous NaBr ,

Bromine  will be collected as reduction potential of Br⁻ is less than O⁻²

in case of aqueous NaF ,

oxygen will be obtained  because reduction potential of F⁻  is more than O⁻² .

5 0
2 years ago
Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.
topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}

Now put all the given values in this formula, we get the moles of calcium hydroxide.

\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0
2 years ago
Which of the following best describes electrolytes
adoni [48]

Answer:

a, b

Explanation:

Electrolytes dissociate to make ions, because of it  they conduct electricity.

4 0
2 years ago
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