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djverab [1.8K]
2 years ago
3

A restaurant catered a party for 40 people. A child’s dinner (c) cost $11 and an adult’s dinner (a) cost $20. The total cost of

the dinner was $728. How many children and adults were at the party? Use the table to guess and check
Mathematics
2 answers:
ycow [4]2 years ago
8 0

Answer:

It Is Actually 8 children and 32 adults!!!

Step-by-step explanation:

sp2606 [1]2 years ago
4 0

Answer:

I think the answers C

Step-by-step explanation:

I seen it off someone elses answer

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Alyssa wants to know the gas mileage of her new car. She kept track of the number of miles she traveled and the number of gallon
Anna [14]

Answer:

D


Step-by-step explanation:

Since Alyssa wants to know her gas mileage, which is MILES PER GALLON, she will need to divide total miles by total gallons.

"per gallon" means per 1 unit of gallon, which we will get ONLY IF WE DIVIDE by TOTAL NUMBER OF GALLONS, hence we get "per unit of gallon".

<u>So we need to divide 243.8 miles by 7.71 gallons to get Alyssa's gas mileage.</u>

Answer choice D is right.

3 0
2 years ago
Which system of equations can be used to find the roots of the equation 12 x cubed minus 5 x = 2 x squared + x + 6? StartLayout
OverLord2011 [107]

Answer:

A

Step-by-step explanation:

12x³-5x=2x²+x+6

y=12x³-5x

y=2x²+x+6

7 0
2 years ago
Two unique letters are chosen at random from the alphabet.
ElenaW [278]
A - choosing letter A first

|\Omega|=P(26,2)=\dfrac{26!}{24!}=25\cdot26\\&#10;|A|=1\cdot25=25\\\\&#10;P(A)=\dfrac{25}{25\cdot26}=\dfrac{1}{26}\approx0.0385
7 0
2 years ago
Read 2 more answers
Given a normal distribution with u = 75 and o = 40, if you select a sample of n = 16, a) what is the probability that the sample
Volgvan

Answer:

a) 0.0228

b) 94.6

Step-by-step explanation:

The formula for calculating a z-score when you are given a random.number of samples is z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation

n = random number of samples

Given a normal distribution with u = 75 and o = 40, if you select a sample of n = 16,

a) what is the probability that the sample mean is above 95? (4 d.p.) b)

= x = 95

Hence:

z = 95 - 75/40/√16

= 20/40/4

= 20/10

= 2

Probability value from Z-Table:

P(x<95) = 0.97725

P(x>95) = 1 - P(x<95) = 0.02275

The probability that the sample mean is above 95 to 4 decimal places = 0.0228

b) What is the value, of which there is 97.5% chance that a sample mean is less than that value?

97.5% chance = z score for the confidence interval = 1.96

Hence:

z = (x-μ)/σ/√n

1.96 = x - 75/40/√16

1.96 = x - 75/ 40/4

1.96 = x - 75/10

Cross Multiply

1.96 × 10 = x - 75

19.6 = x - 75

x = 19.6 + 75

x = 94.6

The value, of which there is 97.5% chance that a sample mean is less than that value is 94.6

5 0
2 years ago
Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
Effectus [21]
Work the information to set inequalities that represent each condition or restriction.

2) Name the variables. 

c: number of color copies
b: number of black-and-white copies

3) Model each restriction:

i) <span>It takes 3 minutes to print a color copy and 1 minute to print a black-and-white copy.
</span><span>
</span><span>3c + b
</span><span>
</span><span>
</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
</span><span>
</span><span>
</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

3c + b ≤ 12
<span />

4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

iv) The final region is the intersection of the above mentioned shaded regions.

v) You can see such graph in the attached figure.

6 0
2 years ago
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