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Bumek [7]
2 years ago
7

Meiosis guarantees that in a sexual life cycle, offspring will inherit one complete set of chromosomes (and their associated gen

es and traits) from each parent. The transmission of traits from parents to offspring is called heredity. Another important aspect of meiosis and the sexual life cycle is the role these processes play in contributing to genetic variation. Although offspring always resemble their parents, they are genetically different from both of their parents and from one another. The degree of variation may be tremendous. The following processes are associated with meiosis and the sexual life cycle: DNA replication before meiosis crossing over chromosome alignment in metaphase I and separation in anaphase I chromosome alignment in metaphase II and separation in anaphase II fertilization Sort each process into the appropriate bin according to whether it contributes to heredity only, genetic variation only, or both. (Note that a bin may be left empty.)
Biology
1 answer:
insens350 [35]2 years ago
6 0

Answer:

HEREDITY ONLY:

none

GENETIC VARIATION ONLY:

none

BOTH:

all

Explanation:

In all the organism that reproduce sexually, produced offspring are genetically varied. As this genetic variation continues, it also leads to hereditary evolution of organism through gene flow from one generation to other. Therefore, the processes of DNA replication, crossing over, chromosome separation and alignment etc. ensure flow of genes from one generation to the next. This does not happen in organisms reproducing asexually.  

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Give one example of how the testing of Platismatia glauca could benefit future ecological research of this forest
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Answer:

Platismatia is a genus of lichens that often is found in forests. Lichens may be beneficial for forests because they provide food and nutrients for other species by fixing atmospheric nitrogen

Explanation:

The lichens are the result of mutualism between photosynthetic organisms (algae or cyanobacteria) and fungi species.

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How are histone modification enzymes (such as HATs) and chromatin remodeling complexes recruited to unmodified chromatin, and ho
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A histone modification mechanism proliferate through a process that includes post translational modification procedure. The methylation, acetylation as well as ubiquitylation are one of the main modifiers that help in activation of silent genes and ultimately these covalently bonded histone modifiers help in regulating chromatin. The PTM has a main role in altering histone structure by these modifier's recruitment....

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2 years ago
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1 year ago
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. Pepper colors range from bright red, orange, and yellow shades, to dark green and brown shades. Coloration in bell peppers is
sattari [20]

Answer:

All crosses and proportions, genotypes and phenotypes are attached.

Explanation:

a. Within living organisms, staining is a characteristic governed by a polygenic inheritance, which means that there is more than one gene involved in the staining process. as you already know, each gene has two alleles, if a trait is controlled by 2 genes, it means that we will have 4 alleles at the crosses.

From the description between dominance and recessivity between the alleles that control the colors of the pepper, shown in the question above, we can see that for the crossing between a red pepper and a green pepper, being able to generate a completely orange offspring, it would be necessary that the genotype of the parent peppers was: Red: RGRG, green: rgrg.

This would generate an orange-colored RrGg offspring, as you can see at the F1 crossing.

b. When individuals of F1 offspring are crossed, the combination of alleles and the determination of genotypes and phenotypes becomes much more complex, because instead of 4 alleles, we will have the combination of 16 alleles among themselves. Once again we will need to rely on the description of dominance and recessivity shown in the question above, so that from the crossing between the alleles of each gene, we can reach a conclusion, as you can see in the F2 crossing.

4 0
1 year ago
In pea plants, the allele for tall stalks (T) is dominant over the allele for short stalks (t). Suppose a cross between a tall p
vazorg [7]

Answer:

Tt - 1/2

tt - 1/2

Explanation:

<em>A cross between a tall pea plant and a short pea plant that produces 43 tall and 47 short offpsring (almost 1:1) is most likely a cross involving a heterozygous tall individual and a homozygous short individual.</em>

Tt   x   tt

Offspring = Tt   Tt   tt   tt (50% tall and 50% short)

If one of the tall offspring (Tt) is crossed with one of the short offspring (tt):

Tt   x   tt

Offspring = Tt   Tt   tt   tt

Genotype ratio = 2Tt:2tt

Hence,

Tt = 1/2

tt = 1/2

6 0
2 years ago
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