Answer:
The correct answer would be Pp.
The genotype of one parent is PP. Thus, it will produce only one type of allele, that is, P.
Similarly, the genotype of another parent is pp. Thus, it will produce only one type of gamete, that is, p.
The cross would produce offspring with only one type of genotype, that is, heterozygous Pp.
The phenotype of all the offspring will be purple as it is a dominant trait.
<span>In the digestive process, the pepsinogen excreted by the walls of the stomach forms the necessary enzyme pepsin when it mixes with hydrochloride acid in the stomach's gastric juices. Pepsin is crucial in breaking down proteins.</span>
It would be B because it says in the question fails to detect auditory changes
Answer:
C) occurs by simple diffusion because lipids are able to penetrate the hydrophobic fatty acid tails within the plasma membrane
Explanation:
After digestion of lipids, monoglycerides and fatty acids associate with bile salts and phopholipids to form micelles. Micelles are structures that are necessary for the transport the poorly soluble monoglycerides and fatty acids to the surface of the enterocyte. But, micelles cannot be absorbed by epithelial cell, only freely dissolved monoglycerides and fatty acids can. Free fatty acids and monogycerids can just diffuse across the plasma membrane because of their nonpolar nature.
Some absorption (e.g. for cholesterol) may be facilitated by specific transport proteins.
Answer:
Codon: 3'-CGC-5'
Codon: 3'-UGC-5'
Explanation:
The anticodons of tRNAs bind to the complementary codons of mRNA. The mRNA codons are always read in 5' to 3' direction. The 5' base of an mRNA codon pairs with 3' base of the anticodon of tRNAs. The first base of the anticodon (the 5' base) determines the number of mRNA codons that are recognized by the tRNA. When the 5' base of the tRNA anticodon is U or G, it binding with codon is less specific. A tRNA anticodon with 5’ G base can read two different codons.
Anticodon: 5'–GCG–3'.
Codon: 3'-CGC-5'
Codon: 3'-UGC-5'
