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taurus [48]
2 years ago
15

Anna wants to estimate the mean number of siblings for each student in her school. She records the number of siblings for each o

f 75 randomly selected students in the school. What is the statistic?a. the specific number of siblings for each randomly selected student
b. all the students in the school
c. the mean number of siblings for all students in the school
d. the mean number of siblings for the randomly selected students
e. the 75 randomly selected students
Mathematics
1 answer:
Sonbull [250]2 years ago
6 0

Answer:

c and d

Step-by-step explanation:

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If 25^x+1 = 125/5^x find the value of x
storchak [24]
  • Answer:

<em>x =1/3</em>

  • Step-by-step explanation:

<em>25ˣ⁺¹ = 125/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³ : 5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³⁻ˣ</em>

<em>2(x + 1) = 3 - x</em>

<em>2x + 2 = 3 - x</em>

<em>2x + x = 3 - 2</em>

<em>3x = 1</em>

<em>x = 1/3</em>

8 0
2 years ago
Tickets for a school play cost $7 and $10 for the adults. The equation 7x+10y=80 represents the number of students(x) and the nu
puteri [66]
There could only be 8 because 10 *8 is 80 and that is your maximum number you can have 
5 0
2 years ago
Vladimir says that the equation of the line that passes through points (negative 5, negative 3) and (10, 9) is y = four-fifths x
Vilka [71]

Answer:

C. both Vladimir and Robyn

Step-by-step explanation:

Just took the test. Hope this helps

5 0
2 years ago
Read 2 more answers
In 1995, the total box office in U.S movie theaters was about $5.02 billion. From 1995 through 2008, the box office revenue incr
soldier1979 [14.2K]

Answer:

1.06 x 10^{10} (3sf)

Step-by-step explanation:

using compound interest formula A = P(1+\frac{R}{100}) ^{n}

from 95 to 08 is 13 yrs

Total Revenue = (5.02 x 10^{9})(1 + \frac{5.9}{100}) ^{13} = 1.057 x 10^{10}

6 0
2 years ago
Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right
Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC²  = CA² and AB=BC

ΔABC isosceles right  angled triangle.

Step-by-step explanation:

Given vectors are  7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = \sqrt{1+1+16} = \sqrt{18}

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC=\sqrt{9+9} =\sqrt{18}

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = \sqrt{16+4+16} =\sqrt{36} =4

Since AB²+BC²  = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle



3 0
2 years ago
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