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Vladimir [108]
2 years ago
7

what would be the amount of a check issued for an 08/11 invoice for 648.50 paid on 09/13 with the terms: 3/10, 2/15, N30-5%APR?

Mathematics
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

The amount of a check issued for an 08/11 invoice, would depend on when the invoice is paid.  

If it's paid within 13 days, there's a 3% discount . which will be calculated as

648.50 x 3% = $19.455 discount

If it's paid within 11 - 15 days, there's a 2% discount.

648.50 x 2% = $12.97 discount

If it's paid within 16 - 30 days, there is no discount

If it's paid after 30 days, 5% APR is added to the bill

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Answer:

See explanation

Step-by-step explanation:

1 step: \overline{GI}\cong \overline {JL} - given

2 step: \overline{GI}\cong \overline{GH}+\overline{HI} - Segments Addition Postulate

3 step: \overline{GH}+\overline{HI}\cong \overline {JL} - Substitution Property

4 step: \overline {JL}\cong \overline {JK}+\overline {KL} - Segments Addition Postulate

5 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {KL} - Substitution Property

6 step: \overline{GH}\cong \overline {KL} - given

7 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {GH} - Substitution Property of Equality

8 step: \overline{HI}\cong \overline {JK} - Subtraction Property of Equality

3 0
2 years ago
on Saturday a bakery sold 6 cakes and several cupcakes a bakery made a total of 165 if Case sell for $12 each and cupcakes sell
lozanna [386]
$12•6=$72

$165-$72=$93

$93/$3= 31 cupcakes

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Subtract $72 from the total $165 dollars made getting $93 left

Divide $93 by the $3 each cupcake cost getting 31 cupcakes

ANSWER: 31 cupcakes sold
3 0
2 years ago
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The P.E. teacher at Sunshine Middle School wants to know which sports are popular among students in her school. Since it would t
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28 BECAUSE IT CONTINUES THE PATTERN OF SUBTRACTING 4 FROMTHE AMOUNT PULLED PER GRADE
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2 years ago
The circumference of a circle varies directly with the radius. A circular pizza with a radius of 3in has a circumference of abou
Morgarella [4.7K]

Answer:

c=kr

c=12.56in when r=2in

Step-by-step explanation:

Circumference (c) of a circle varies directly with radius(r)

Equation that relates the circumference and radius is

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Radius=3in

Circumference=18.84in

18.84=k*3

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3 0
2 years ago
1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th
Kryger [21]

Answer:

a

  P = 0  OR  P = 135

b

P > 0 and P < 135

OR

P > 0 and P < 135

c

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

d

P = 67.5

Step-by-step explanation:

From the question we are told that

The population model is \frac{dP}{dt}  =  0.2P(1 - \frac{P}{135} )

Generally at equilibrium

\frac{dP}{dt} = 0

So

0.2P = 0

=> P = 0

Or

(1 - \frac{P}{135} ) = 0

=> P = 135

Thus at equilibrium P = 0 or P = 135

Generally when the population is increasing we have that

\frac{dP}{dt} > 0

So

0.2P > 0

=> P > 0

and

(1 - \frac{P}{135} ) > 0

P < 135

Now when the first value of P i.e P< 0 for \frac{dP}{dt} > 0

P_2 > 135

So when population increasing the values of P are

P > 0 and P < 135

OR

P > 0 and P < 135

So to obtain initial values of P where the population converge to the carrying capacity as t \to [\infty]

The rate equation can be represented as

\frac{dP}{dt}  =  \frac{1}{5}P (1 - \frac{P}{135} )

So we will differentiate the equation again we have that

\frac{d^2 P}{dt^2} = \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675}

Now as  t \to [\infty]

\frac{d^2 P}{dt^2} \to  0

So

   \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675} = 0      

=>    \frac{(1 - \frac{P}{135} )}{5}   =  \frac{P}{675}

=> P = 67.5

5 0
2 years ago
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