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Harlamova29_29 [7]
2 years ago
8

A 3.78-gram sample of iron metal is reacted with sulfur to produce 5.95 grams of iron sulfide. Determine the empirical formula o

f this compound.
Chemistry
2 answers:
Alexeev081 [22]2 years ago
8 0

Answer:

The answer to your question is FeS₃

Explanation:

Data

mass of Fe = 3.78g

mass of S = 5.95 g

mass of FeS

Chemical Balanced Reaction

                           Fe   +   S     ⇒    FeS

Process

1.- Convert the grams to moles

For Iron

                              55.85g of Fe --------------  1 mol

                               3.78 g of Fe -----------  x

                               x = (3.78 x 1) / 55.85

                               x = 0.0677 moles

For Sulfur

                              32 g of S ------------------- 1 mol

                               5.95 g     ------------------  x

                               x = (5.95 x 1)/32

                               x = 0.185 moles

2.- Divide by the lowest number of moles

Iron = 0.0677 /0.0677 = 1

Sulfur = 0.185 /0.0677 = 2.73 ≈  3

3.- Write the empirical formula

                                 FeS₃                                

lilavasa [31]2 years ago
5 0

Answer:FeS

Explanation:

Mass of sulphur=5.95-3.78=2.17g

Fe S

3.78/56. 2.17/32

0.0675/0.0675. 0.0678/0.0675

1:1

Empirical formula=Fe1S1=FeS

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Select the correct answer.
Phoenix [80]

Answer:

Molecular formula =  C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 31.7 g

Mass of carbon = 283.4 g

Mass of oxygen = 377.4 g

Molar mass of compound = 176.124 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of H = 31.7 / 1.01 = 31.4

Number of gram atoms of O = 377.4 / 16 = 23.6

Number of gram atoms of C = 283.4 / 12 = 23.6

Atomic ratio:

            C                      :      H                 :         O

           23.6/23.6         :     31.4/23.6     :       23.6/23.6

              1                      :        1.33              :        1

C : H : O =3 (1 : 1.33 : 1 )

Empirical formula is C₃H₄O₃.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+4+3×16 = 88

n = 176.124 / 88

n = 12

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₄O₃)

Molecular formula =  C₆H₁₂O₆

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2 years ago
Elena has two magnets. She puts one under a piece of paper. She holds the other one above it. The magnets attract each other. Th
Sonbull [250]
A) Magnets can attract through solid materials.
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2 years ago
Which of the samples described below contains the FEWEST atoms? No calculation is needed to answer this question.
Monica [59]

Hello!

To do this, use the molar mass. This is how much a mole of an atom weighs. A mole is 6.02214076×10²³ atoms.

Molar masses of:

Se: 78.96 g/mol

Cu: 63.546 g/mol

Ba: 137.327 g/mol

Now, the element with the highest molar mass will have the fewest atoms. This is because the element weighs more, so therefore for the same amount of mass, there will be less of the element needed to reach that mass.

Therefore, 10g of Ba would have the fewest number of atoms.

Hope this helps!

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2 years ago
Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 ∘C? (HINT: the act
svp [43]

Explanation:

Below is an attachment containing the solution.

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2 years ago
Write the word equation for the reaction of barium nitride with potassium
Irina18 [472]

Answer:

Well this is a metathesis or partner exchange reaction....and barium sulfate is as soluble as a brick...

Explanation:

And so...

Ba(NO3)2(aq)+K2SO4(aq)→2KNO3(aq)+BaSO4(s)⏐↓

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Explanation:

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