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umka2103 [35]
2 years ago
9

A sample of soil from a newly discovered cave is analyzed by a team of explorers. They find an element that is a good conductor

of electricity. It also forms a chloride in the form XCl2 and an oxide in the form XO. The element is a liquid at room temperature. What is the identity of this element? Express your answer using a chemical symbol.
Chemistry
1 answer:
kipiarov [429]2 years ago
4 0

Answer:

Hg

Explanation:

We are given information about the unknown element, and using each characteristic, we can narrow down the possible elements until we have just one possibility left.

Conducts electricity: This means that the element has to be a metal, or a semi-metal, because non-metals cannot conduct electricity.

Forming chloride and oxide ions: When it is seen that it forms chloride and oxide ions in the form of XCl₂ and XO, it can be seen that this element has an ionic charge of +2. This narrows it down to the elements in <u>Group 2.</u>

Liquid at room temperature: This is tricky, because we realize that there are no elements in group 2 that are liquid at room temperature. So hence we can look at groups 3 to 12, and see if there are any liquid metals with an ionic charge of +2.

Taking all this information into account, we can see that the only element it can be is mercury (Hg).

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Which of the following is the best piece of laboratory glassware for preparing 500.0 mL of an aqueous solution of a solid?
Leni [432]

Answer:

The correct answer is option A.

Explanation:

Volumetric flask  : A glass ware with round lower body with flat bottom and with thin cylindrical neck along with mark which indicates the specific volume filled to that mark.It is used in preparation of standard solution of compound with desired concentration with fixed volume.

Erlenmeyer flask : is a flask with conical shape with flat bottom used in titration  experiments to carry out reaction with fixed volume of solution.

Test tube : Small cylindrical tube with rounded bottom used to observe reaction in between reactant taken in small amount.

Graduated beaker : Laboratory glassware used measure larger volumes of solution or to mix or stir solutions and liquids.

Graduated cylinder : Laboratory thin cylindrical glassware with accurate marking of volume used to measure an accurate volume of solutions or liquids required in an experiment.

<em><u>Volumetric flask</u></em> is the best piece of laboratory glassware for preparing 500.0 mL of an aqueous solution of a solid

8 0
2 years ago
Read 2 more answers
Choose the answer in which the three atoms and/or ions are listed in order of increasing EXPECTED size (smallest particle listed
svp [43]

Answer:

Ar < Cl - < S2-

Explanation:

All the species written above are isoelectronic. This means that they all possess the same number of electrons. All the species above possess 18 electrons, the noble gas electron configuration.

However, for isoelectronic species, the greater the atomic number of the specie, the smaller it is. This is because, greater atomic number implies that their are more protons in the nucleus exerting a greater attractive force on the electrons thereby making the specie smaller in size due to high electrostatic attraction.

8 0
2 years ago
What is the pOH of a 1 x 10^-8 M solution of HNO3?
Sedaia [141]

Explanation:

to find POH u need PH first

so ph=-log(h3o)

so

ph =  -  log(1 \times  {10}^{ - 8} )  \\  \\ ph = 8 \\ ph + poh =14 \\ poh = 14 - 8 \\ poh = 6

8 0
1 year ago
11. If there are 8.24 x 1022 molecules of NaCl in a salt shaker, what is the mass of the salt?
vlada-n [284]

Answer: 8.12 g NaCl

Explanation: Use Avogadro's number to find the number of m

moles of NaCl:

8.24x10²² molecules NaCl / 1 mole NaCl/ 6.022x10²³ molecules NaCl

= 0.14 mole NaCl

Next convert moles to grams NaCl using its molar mass;

0.14 mole NaCl x 58g NaCl / 1 mole NaCl

= 8.12 g NaCl

6 0
2 years ago
Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that
Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

<u />

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

<u />

See figure 1 to further explanations.

I hope it helps!

<u />

<u />

8 0
2 years ago
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