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matrenka [14]
2 years ago
15

In which of the following examples does the object have both kinetic and potential energy? Select all that apply.

Physics
1 answer:
Andru [333]2 years ago
8 0

Objects having both kinetic and potential energy:

water flowing downstream

a child swinging on a swing

a bouncing ball

a plane in flight at 30,000 feet

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

Therefore, an object has kinetic energy when its speed is non-zero (so, whenever it is moving).

The potential energy of an object is the energy possessed by the object due to its position in the gravitational field. It is given by

PE=mgh

where

m is the mass

g is the acceleration of gravity

h is the heigth of the object relative to the ground

Therefore, an object has potential energy whenever it is located at a certain height above the ground.

So in this problem, the objects that have both kinetic and potential energy are:

a rock at the edge of a cliff  --> NO, because the rock is at rest (so KE = 0)

water flowing downstream  --> YES, because the water is moving AND it is at a certain height above the ground

a child swinging on a swing  --> YES, because the child is moving AND it is at a certain height above the ground

a bouncing ball  --> YES, because the ball is moving AND it is at a certain height above the ground

water behind a dam  --> NO, because the water is at rest (so KE=0)

a car moving on a level road  --> NO, because the car is at ground level (so PE=0)

a plane in flight at 30,000 feet   --> YES, because the plane is moving AND it is at a certain height above the ground

a compressed spring --> NO, because the spring is at rest (so KE=0)

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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\Delta U = q (V_2 -V_1)=q \Delta V

In our problem, the electron (charge e) must travel across a potential difference V. So the energy it will lose traveling from the metal to the detector will be equal to 
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5 0
2 years ago
Th e heat capacity of air is much smaller than that of water, and relatively modest amounts of heat are needed to change its tem
Darina [25.2K]

Answer:

Q=1005 J

t= 0.67 sec

Explanation:

Lets take condition of room is 1 atm and 25°C.

Heat capacity ,c = 21 J /K.mol

If we assume that air is ideal gas that

P V = n R T

V= 5.5\times 6.5\times 3\ m^3

V=107.25\ m^3

V=107.25\times 1000 L

V= 107250 L

At STP number of moles given as

n=\dfrac{V}{V_{at\ S.T.P.}}

V=22.4 L at S.T.P.

n=\dfrac{107250}{22.4}\ moles

n=4787.94 moles

n= 4.784 Kmoles

So heat required to raise 10°C temperature

Q = n x c x ΔT

Q = 4.78794 x 21 x 10

Q=1004.64 J

Time t

t= Q/P

P= 1.5 KW

t = 1.004.64 /1.5

t= 0.66 sec

4 0
2 years ago
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Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in
Tatiana [17]

Explanation:

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1) Density of gasoline = 0.748 g/cm^3

Density of the gasoline is less than the the density of corn syrup which means it will float in corn syrup.

2) Density of water = 1 g/cm^3

Density of the water is less than the the density of corn syrup which means it will float in corn syrup.

3) Density of honey = 1.45 g/cm^3

Density of the gasoline is more than the the density of corn syrup which means it will sink in corn syrup.

4) Density of titanium = 4.506 g/cm^3

Density of the titanium is more than the the density of corn syrup which means it will sink in corn syrup.

3 0
2 years ago
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Alex Ar [27]
Ans: 
1.  τbiceps = +(Positive)
2.  τforearm = -(Negative)
3.  τball = -(Negative)

Explanation:

The figure is attached down below.

1. T<span>orque about the elbow caused by the biceps, τbiceps:
Since Torque = r x F (where r and F are the vectors)
</span>Where r is the vector from elbow to the biceps.
<span>
We can see in the figure that F(biceps) is in upward direction, and by applying the right hand rule from r to F, we get the counterclockwise direction. The torque in counterclockwise direction is positive(+). Therefore, the sign would be +.

2. </span>Torque about the the weight of the forearm, τforearm:
Since Torque = r x F (where r and F are the vectors)
Where r is the vector from elbow to the forearm.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(forearm) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

3. Torque about the the weight of the ball, τball:
Since Torque = r x F (where r and F are the vectors)
Where r is the vector from elbow to the ball.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(ball) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

8 0
2 years ago
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dmitriy555 [2]

Answer:14 m

Explanation:

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substitute the value of u^2

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R=2h\sin 2\theta

Range will be maximum for \theta =45^{\circ}

thus R_{max}=2\times 7\times 1=14\ m

                                     

3 0
2 years ago
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