A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If
1 answer:
11.43g/mL
Explanation:
Given parameters:
Volume of water in the graduated cylinder = 100mL
Volume of water + lead weight = 450mL
Mass of lead weight = 4000g
Unknown:
Density of the lead weight = ?
Solution:
Density is the mass per unit volume of a body.
Density =
Volume of the lead weight = volume of water displaced
Volume of lead weight = 450 - 100 = 350mL
Density = = 11.43g/mL
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2KMnO4 + 5H2O2 + 3H2SO4 → 2MnSO4 + K2SO4 + 5O2 + 8H2O
From the above balance reaction, it can be seen that 2 moles of KMnO4 is consumed for every 5 moles of H2O2.
Now, percent by mass of hydrogen peroxide in the original solution can be estimated as follows:
percent by mass =
∴percent by mass =
= 4 %
2KMnO4 + 5H2O2 + 3H2SO4 → 2MnSO4 + K2SO4 + 5O2 + 8H2O
From the above balance reaction, it can be seen that 2 moles of KMnO4 is consumed for every 5 moles of H2O2.
Now, percent by mass of hydrogen peroxide in the original solution can be estimated as follows:
percent by mass =
∴percent by mass =
= 4 %