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horsena [70]
2 years ago
11

A fast-moving wet slurry consisting of a mixture of water and volcaniclastic debris is termed a ________.

Chemistry
1 answer:
Soloha48 [4]2 years ago
6 0

Answer:

A fast-moving wet slurry consisting of a mixture of water and volcaniclastic debris is termed a lahar

Explanation:

A lahar is a debris flow or mud-flow that consists of a mixture of volcanic material, rock particles and water, flowing typically along a river valley down from a volcano

Lahars can be either from either pyroclastic flows or heavy rainfall after a volcanic eruption

Lahars are hazardous as they can result in destruction, severe damage destroying buildings and some times entire small towns are wiped out. This is more so as they move silently and very fast down to the valleys

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A gem has a mass of 4.50 g. When the gem is placed in a graduated cylinder 12.00 mL of water, the water level rises to 13.45 mL.
Mandarinka [93]
<span>Displaced volume :

</span>Final volume - <span>Initial volume

</span>13.45 mL - 12.00 mL => 1.45 mL

Mass =  4.50 g

Therefore:

density = mass / volume

D = 4.50 / 1.45

<span>D = 3.103 g/mL </span>
6 0
2 years ago
Name one manufactured device or natural phenomenon that emits electromagnetic radiation in each of the following wavelengths: ra
Bas_tet [7]
Radio - Radio station transmits radio wavelength which is received by the
Radio. 
<span>
Microwaves - Microwave Oven to heat up foods. </span>

<span>IR (infrared) - TV remote Control, to transmit IR light to a sensor in the TV so it can do some functions like increasing the volume, changing the channel etc. </span>


<span>Visible light - Sunlight or Light Bulbs </span>

<span>Ultraviolet - UV Lamps for sun tan, for detecting forged money </span>

<span>X-rays - Chest X-ray machines, Backscatter Xray (body scanner in airport security)
</span>
Gamma rays - Gamma rays<span> Medical Equipment which are used to kill cancer cells, to sterilize medical </span>equipment<span> </span>
7 0
2 years ago
A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
REY [17]

Answer:

Sn_2O

Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO

In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1

Therefore, the empirical formula is:

Sn_2O

Best regards.

8 0
2 years ago
Which describes any compound that has at least one element from group 17?
Contact [7]
The answer is HALIDE.
6 0
2 years ago
A 0.2-mm-thick wafer of silicon is treated so that a uniform concentration gradient of antimony is produced. One surface contain
krek1111 [17]

Answer:

- 0.0249% Sb/cm

-1.2465 * 10^9 \frac{atoms}{cm^3.cm}

Explanation:

Given that:

One surface contains 1 Sb atom per  10⁸  Si atoms and the other surface contains 500 Sb atoms per  10⁸ Si atoms.

The concentration gradient in atomic percent (%) Sb  per cm can be calculated as follows:

The difference in concentration = \delta_c

The distance \delta_x = 0.2-mm = 0.02 cm

Now, the concentration of silicon at one surface containing  1 Sb atom per 10⁸ silicon atoms and at the outer surface that has 500 Sb atom per   10⁸ silicon atoms can be calculated as follows:

\frac{\delta_c}{\delta_c} = \frac{(1/10^8 -500/10^8)}{0.02cm} *100%

= - 0.0249% Sb/cm

b) The concentration (c_1) of Sb in atom/cm³ for the surface of 1 Sb atoms can be calculated by using the formula:

c_1 = \frac{(8 si atoms/unit cells)(1/10^3)}{(lattice parameter)^3/unit cell}

Lattice parameter = 5.4307 Å;  To cm ; we have

= 5.4307A^0* \frac{10^{-8}cm}{ A^0}

c_1 = \frac{(8 si atoms/unit cells)(1/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}

= 0.00499*10^{17}atoms/cm^3

The concentration (c_2) of Sb in atom/cm³ for the surface of 500 Sb can be calculated as follows:

c_1 = \frac{(8 si atoms/unit cells)(500/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}

   =  \frac{4*10^{-3}}{1.601*10^{-22}}

   = 2.4938*10^{17}atoms/cm^3

Finally, to calculate the concentration gradient

(\frac{\delta _c}{\delta_ x}) = \frac{c_1-c_2}{\delta_x}

(\frac{\delta _c}{\delta_ x}) = \frac{0.00499*10^{17}-2.493*10^{17}}{0.02}

= -1.2465 * 10^9 \frac{atoms}{cm^3.cm}

8 0
2 years ago
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