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julsineya [31]
2 years ago
12

A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final vol

ume of the solution is 576 mL.
Chemistry
1 answer:
oee [108]2 years ago
5 0

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>

545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>

Thus, mole fraction of fructose is:

\frac{0,509 moles}{0,509mol + 30,24mol} = 0,0166

<em>Mole fraction = 0,0166</em>

I hope it helps!

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Answer:

Explanation:

q= mc theta

where,

Q = heat gained

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Now put all the given values in the above formula, we get the amount of heat needed.

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