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ira [324]
2 years ago
12

The graph shown could represent which of these? A) A book released from a height with the dotted line representing potential ene

rgy and the solid line representing kinetic energy. B) A book released from a height with the dotted line representing kinetic energy and the solid line representing potential energy. C) A pendulum released from a height with the dotted line representing potential energy and the solid line representing kinetic energy. D) A pendulum released from a height with the dotted line representing kinetic energy and the solid line representing potential energy.
Chemistry
2 answers:
Nadya [2.5K]2 years ago
7 0

Answer:

C: A pendulum released from a height with the dotted line representing potential energy and the solid line representing kinetic energy.

Explanation

jekas [21]2 years ago
3 0

Hey ur amswer is C


I hope this helps

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Which processes occur during the second stage of technological design? Check all that apply.
Lena [83]
There is four stages of technological design:1. identify a problem or need.2. design a solution.3. implement, build, test the design.4. determine if the solution met the need.To design a solution is second stage of technological design.
3 0
2 years ago
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Perform the following
Ghella [55]

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

4 0
2 years ago
40pionts
Pachacha [2.7K]

Problem One (left)

This is just a straight mc deltaT question

<em><u>Givens</u></em>

m = 535 grams

c = 0.486 J/gm

tf = 50

ti = 1230

Formula

E = m * c * (ti - tf)

Solution

E = 535 * 0.486 * ( 1230 - 50)

E = 535 * 0.486 * (1180)

E = 301077

Answer: A

Problem Two

This one just requires that you multiply the two numbers together and cut it down to 3 sig digits.

E = H m

H = 2257 J/gram

m = 11.2 grams

E = 2257 * 11.2

E = 25278  to three digits is 25300 Joules. Anyway it is the last one.

Three

D and E are both incorrect for the same reason. The sun and stars don't contain an awful lot of Uranium (1 part of a trillion hydrogen atoms). It's too rare. The other answers can all be eliminated because U 235 is pretty stable in its natural state. It has a high activation complex.

Your best chance would be enriched Uranium (which is another way of saying refined uranium). That would be the right environment. Atomic weapons and nuclear power plants (most) used enriched Uranium. You can google "Little Boy" if you want to know more.

Answer: B

Four

The best way to think about this question is just to get the answer. Answer C.

A: incorrect. Anything sticking together implies a larger and larger result. Gases don't work that way. They move about randomly.

B: Wrong. Heat and Temperature especially depend on movement. Stopping is not permitted. If a substance's molecules stopped, the substance would experience an extremely uncomfortable temperature drop.

C: is correct because the molecules neither stop nor do they stick. The hit and move on.

D: Wrong. An ax splitting something? That is not what happens normally and not with ordinary gases. It takes more energy that mere collisions or normal temperatures would provide to get a gas to split apart.

E: Wrong. Same sort of comment as D. Splitting is not the way these things work. They bounce away as in C.

Five

Half life number 1 would leave 0.5 grams behind.

Half life number 2 would leave 1/2 of 1/2 or 1/4 of the number of grams left.

Answer: 0.25

Answer C

6 0
2 years ago
A government laboratory wants to determine whether water in a certain city has any traces of fluoride and whether the concentrat
vladimir2022 [97]
"<span>30.4 ppm > 4 ppm, unsafe to drink" is the one among the following choices given in the question that shows that the water should be declared unsafe for drinking. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that the answer has helped you.</span>
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2 years ago
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What is the density of 2.5 g of gaseous sulfur held at 130. kPa and 10.0 degrees Celsius?
worty [1.4K]
Use ideal gas equation: pV = nRT

Now pass n to mass: n = mass / MM .... [MM is the  molar mass]

pV = [mass/MM]*RT =>mass/V = [p*MM] / RT  and mass / V = density

p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol  = 32000 kg/mol

density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L  ≈ 1.8 g/L

Then, I do not get any of the option choices.

Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L

Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.



 
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2 years ago
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