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svet-max [94.6K]
2 years ago
14

The following set of solutions are prepared by dissolving the requisite amount of solute in water to obtain the desired concentr

ations. The pressure of the system is then manipulated such that movement is from the solution listed first to the solution listed second.Classify each set of solutions based on the movement of solvent from the first solution listed to the second solution listed as osmosis or reverse osmosis. 1. 4.2 M HNO3 to 2.4 M HNO3 2. 0.4 M NaCl to 0.8 M NaCl 3. 1 M KOH to 2 M KOH 4. 0.6 M KCl to 0.3 M KCl 5. 1 M CH3COOH to 0.4 M CH3COOH 6. 0.01 M Sucrose to 1 M Sucrose
Chemistry
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

1. Reverse osmosis

2. Osmosis

3. Osmosis

4. Reverse osmosis

5. Reverse osmosis

6. Osmosis

Explanation:

The osmosis is the process when the solvent goes through a membrane from a side with a low concentration of solute to a higher concentration, to achieve an equilibrium. When the movement is doing on the opposite side (from higher concentration to low), the process is called reverse osmosis.

1. It is going from a higher to a low concentration, so it's reverse osmosis.

2. It's going from a low to a higher concentration, so it's osmosis.

3. It's going from a low to a higher concentration, so it's osmosis.

4. It is going from a higher to a low concentration, so it's reverse osmosis.

5. It is going from a higher to a low concentration, so it's reverse osmosis.

6. It's going from a low to a higher concentration, so it's osmosis.

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Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:

48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ

<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>    
5 0
2 years ago
What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k
marshall27 [118]
Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

                                            d  =  P M / R T         -------  (1)
Where;
P  = Pressure =  1.03 atm

M  = Molar Mass =  146.06 g/mol

R  = Gas Constant =  0.08206 atm.L.mol⁻¹.K⁻¹

T  = Temperature =   297 K

Putting Values in eq. 1,

           d  =  (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

                                          density  =  6.17 g/L
6 0
2 years ago
When 13.6 g of calcium chloride, CaCl2, was dissolved in 100.0 mL of water in a coffee cup calorimeter, the temperature rose fro
DanielleElmas [232]

Answer:

THE ENTHALPY OF SOLUTION IS 3153.43 J/MOL OR 3.15 KJ/MOL.

Explanation:

1. write out the variables given:

Mass of Calcium chloride = 13.6 g

Change in temperature = 31.75°C - 25.00°C = 6.75 °C

Density of the solution = 1.000 g/mL

Volume = 100.0 mL = 100.0 mL

Specific heat of water = 4.184 J/g °C

Mass of the water = unknown

2. calculate the mass of waterinvolved:

We must first calculate the mass of water in the bomb calorimeter

Mass = density  * volume

Mass = 1.000 * 100

Mass = 0.01 g

3. calculate the quantity of heat evolved:

Next is to calculate the quantity of heat evolved from the reaction

Heat = mass * specific heat of water * change in temperature

Heat = mass of water * specific heat *change in temperature

Heat = 13.6 g * 4.184 * 6.75

Heat = 13.6 g * 4.184 J/g °C * 6.75 °C

Heat = 384.09 J

Hence, 384.09J is the quantity of heat involved in the reaction of 13.6 g of calcium chloride in the calorimeter.

4. calculate the molar mass of CaCl2:

Next is to calculate the molar mas of CaCl2

Molar mass = ( 40 + 35.5 *2) = 111 g/mol

The number of moles of 13.6 g of CaCl2 is then:

Number of moles of CaCl2 = mass / molar mass

Number of moles = 13.6 g / 111 g/mol

Number of moles = 0.1225 mol

So 384.09 J of heat was involved in the reaction of 1.6 g of CaCl2 in a calorimter which translates to 0.1225 mol of CaCl2..

5. Calculate the enthalpy of solution in kJ/mol:

If 1 mole of CaCl2 is involved, the heat evolved is therefore:

Heat per mole = 384.09 J / 0.1225 mol

Heat = 3 135.43 J/mol

The enthalpy of solution is therefore 3153.43 J/mol or 3.15 kJ/mol.

5 0
2 years ago
A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h
Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

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Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}

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3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles =  0.00575 moles

Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}

Molarity of HCl left un-neutralized :\frac{0.00575 moles}{0.350L}=0.0164 M

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0
2 years ago
A deck of cards has dimensions 8.9cm x 5.72cm x 1.82 cm. What is the volume of the deck in cubic centimeters?
arsen [322]

Answer:

92.65256 cm^3

Explanation:

To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.

5 0
2 years ago
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