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ANEK [815]
2 years ago
3

The question refers to the following species. (A) H2O (B) NH3 (C) BH3 (D) CH4 (E) SiH4 Is predicted to have the largest bond ang

le
Chemistry
1 answer:
artcher [175]2 years ago
5 0

Answer:

BH_3

Explanation:

Hybridization in H_2O is sp3. Two bond pair and two lone pairs are present. Bond angle of molecule having sp3 hybridization is 109°5”. Because of lone pair, bond angle reduced to 104.5.

In NH_3, hybridization is sp3 and have three bond pairs and one lone pair. Because of lone pair, bond angle in NH3 is 107°.

In BH_3, hybridization is sp^2 with three bond pairs.  

Bond angle of molecule having sp2 hybridization is 120°. As no lone pair is present. Therefore, bond angle will be 120°.

In CH_4 and SiH_4, hybridization is sp^3 with 4 bond pairs. As no lone pair is present. Therefore, bond angle in both the molecules will be 109°5”.

Therefore, among given, BH_3 will have highest bond angle.

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Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that
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Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

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2 years ago
Find the number of moles of water that can be formed if you have 170 mol of hydrogen gas and 80 mol of oxygen gas. Express your
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<u>Answer:</u> The amount of water that can be formed is 160 moles

<u>Explanation:</u>

We are given:

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Moles of oxygen gas = 80 moles

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

2H_2+O_2\rightarrow 2H_2O

By Stoichiometry of the reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas

So, 80 moles of oxygen gas will react with = \frac{2}{1}\times 80=160mol of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of oxygen gas produces 2 moles of water

So, 80 moles of oxygen gas will produce = \frac{2}{1}\times 80=160moles of water

Hence, the amount of water that can be formed is 160 moles

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