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user100 [1]
2 years ago
10

Hydrogen has three isotopes with mass numbers of 1, 2, and 3 and has an average atomic mass of 1.00794 amu. This information ind

icates that
1. equal numbers of each isotope are present
2. more isotopes have an atomic mass of 2 or 3 than of 1
3. more isotopes have an atomic mass of 1 than of 2 or 3
4. isotopes have only an atomic mass of 1
Chemistry
2 answers:
Rama09 [41]2 years ago
8 0

<u>Answer:</u> The information indicates more isotopes have an atomic mass of 1 than of 2 or 3

<u>Explanation:</u>

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

We are given:

Three isotopes of Hydrogen, which are H-1, H-2 and H-3

Average atomic mass of hydrogen = 1.00794 amu

As, the average atomic mass of hydrogen is closer to the mass of H-1 isotope. This means that the relative abundance of this isotope is the highest as compared to the other two isotopes.

Percentage abundance of H-1 isotope = 99.98%

Percentage abundance of H-2 isotope & H-3 isotope = 0.02 %

Hence, the information indicates more isotopes have an atomic mass of 1 than of 2 or 3

ki77a [65]2 years ago
7 0

Answer:its actually 3 trust me

Explanation:

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ke prop to v^2


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400/50x50=joules/100x100


400x2x2


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2 years ago
For a solar eclipse to occur which of the following alignments is necessary? A. The moon is located along a straight line betwee
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A. I'm pretty sure, could be C though..

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2 years ago
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vredina [299]

Answer:

volume in L = 0.25 L

Explanation:

Given data:

Mass of Cu(NO₃)₂ = 2.43 g

Volume of KI = ?

Solution:

Balanced chemical equation:

2Cu(NO₃)₂  + 4KI    →    2CuI + I₂ + 4KNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 2.43 g/ 187.56 g/mol

Number of moles = 0.013 mol

Now we will compare the moles of Cu(NO₃)₂ with KI.

                        Cu(NO₃)₂       :              KI    

                              2              :               4

                            0.013          :            4 × 0.013=0.052 mol

Volume of KI:

<em>Molarity = moles of solute / volume in L</em>

volume in L = moles of solute /Molarity

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volume in L = 0.25 L

6 0
2 years ago
For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of t
makvit [3.9K]

Answer:

\frac{N_{v}}{N}=1.92*10^{-4}

Explanation:

First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.

7.40 \frac{g}{cm^{3}}*\frac{1mol}{85.5 g}*\frac{6.023*10^{23}atoms}{1mol}*\frac{1000000 cm^{3}}{1m^{3}}=5.21*10^{28}\frac{atoms}{m^{3}}

Now, the fraction of vacancies is equal to the N(v)/N ratio.

  • N(v) is the number of vacancies 1*10^{25}m^{-3}
  • N is the number of atoms per volume calculated above.

Therefore:  

The fraction of vacancies at 600 °C will be:

\frac{N_{v}}{N}=\frac{1*10^{25}}{5.21*10^{28}}  

\frac{N_{v}}{N}=1.92*10^{-4}

I hope it helps you!

 

7 0
2 years ago
Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?
Margarita [4]

Answer:

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Explanation:

Positron emission involves the conversion of a proton to a neutron. This process increases the mass number of the daughter nucleus by 1 while its atomic number remains the same. The new neutron increases the number of neutrons present in the daughter nucleus hence the process increases the N/P ratio.

A positron is usually ejected in the process together with an anti-neutrino to balance the spins.

6 0
2 years ago
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