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Bingel [31]
2 years ago
13

Suppose a triangle has sides a, b, and c, and that a2 + b2 < c2. Let be the measure of the angle opposite the side of length

c. Which of the following must be true? Check all that apply.
A. the triangle is not a right triangle.
B. a^2+b^2-c^2=2abcos(theta)
C. cos(theta) > 0
D. cos(theta) < 0
Mathematics
1 answer:
Sav [38]2 years ago
5 0

Answer:

the answer is ?

Step-by-step explanation:

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3 (n - 1) + 2 (n + 2)
Vikentia [17]
3n - 3 + 2n + 4
(3n + 2n) + (-3 + 4)
5n + 1
5 0
2 years ago
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The table gives the probabilities that orphaned pets in animal shelters in six cities are one of the types listed.
vagabundo [1.1K]

Answer:

the ablity to choose one is the right now

Step-by-step explanation:

3 0
2 years ago
Monica has a bag of marbles. There are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick
natima [27]

Answer:

\frac{7}{64}\approx 0.11

Step-by-step explanation:

We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.

Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.          

Since the probability of two independent compound events is always the product of probabilities of both events.

P(\text{A and B})=P(A)*P(B)

Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.

P(Red)=\frac{\text{Total red marbles}}{\text{Total marbles}}

P(Red)=\frac{4}{16}

Probability of picking blue ball out of 16 (4+7+5) marbles:

P(Blue)=\frac{\text{Total blue marbles}}{\text{Total marbles}}

P(Blue)=\frac{7}{16}

Now let us find probability of Monica picking a red and then a blue marble.

P(\text{Red and Blue})=\frac{4}{16}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{1}{4}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{7}{4*16}

P(\text{Red and Blue})=\frac{7}{64}

P(\text{Red and Blue})=0.109375\approx 0.11

Therefore, the probability of picking a red and then blue marble is \frac{7}{64}\approx 0.11.  

7 0
2 years ago
At the amusement park, Laura paid $6.00 for a small cotton candy. Her older brother works at the park, and he told
BabaBlast [244]

Answer:

yes

The price of marked up candy is $6.00

perentage of mark up is 300%

let the marked up amount be represented as x

let 300% mark up be represented as 3x

the equatiopn for finding the price before markup

can be represented as 3x-x=$6.

                                    2x=$6

                                    x=$3.

8 0
2 years ago
20% of the tickets sold at a water park were adult tickets. If the park sold 55 tickets in all,how many did it sell?
djyliett [7]

Answer:

11 adult tickets

Step-by-step explanation:

I guess you want the number of adult tickets sold.

That is 20% of 55

= 0.20*55

= 11 (answer)

8 0
2 years ago
Read 2 more answers
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