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Naily [24]
2 years ago
12

A chemist mixes 75.0 g of an unknown substance at 96.5C w/ 1,150 g of water at 25.0C . if the final temperature of the system is

37.1C, what is the specific heat capacity of the substance ? Use 4.184 J /g Celsisus for the specific heat capacity of water.
a. 368
b. 13.1
c. 0.368
d. 0.0112
Chemistry
1 answer:
vichka [17]2 years ago
3 0
Remember: heat lost = heat gained 

When calculating heat loss or gain, remember 

mass*(spec heat cap)*(change in T) 

The unknown loses heat- we don't know the spec heat cap, so we'll call it x.

The water gains. I've omitted the units, but always use when solving problems on your own. 

75*x*(96.5-37.1) = 1150*4.184*(37.1-25) 
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Now it's all set up- use algebra to get x, the spec heat cap of the unk in J/g*degC

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Barry Bonds swings a bat which has a mass of 1.5 kg at a velocity of 55 m/s. How many joules of kinetic energy could he give to
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KE = mv2
2
KE = ? J
m = 1.5 kg
v = 55 m/s
KE = 1.5 kg x (55 m/s)2
2
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2 years ago
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A student builds a model of a race car. The scale is 1:15. In the scale model, the car is 8 cm tall.How tall is the actual car?
Xelga [282]

let the actual height of car be x

now, according to question,

  • \dfrac{1}{15}  =  \dfrac{8}{x}

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5 0
1 year ago
A gas cylinder filled with nitrogen at standard temperature and pressure has a mass of 37.289 g. The same container filled with
andrew-mc [135]

Answer:

Molar mass = 3.9236 g/mol ≅ 4 g/mol

This corresponds to Helium gas.

Explanation:

Let the moles of nitrogen gas = x moles

Moles of carbon dioxide = x moles ( As both are filled at same temperature and pressure conditions )

Given:

Mass_{Container}+Mass_{Nitrogen\ gas}=37.289\ g

Molar mass of nitrogen gas, N_2 = 28.014 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

x\ moles= \frac{Mass}{28.014\ g/mol}

Mass of nitrogen gas = 28.014x g

So,

Let, Mass_{Container}=y

y+28.014x=37.289

Similarly,

Mass_{Container}+Mass_{Carbon\ dioxide\ gas}=37.440\ g

Molar mass of nitrogen gas, CO_2 = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

x\ moles= \frac{Mass{44.01\ g/mol}

Mass of nitrogen gas = 44.01x g

So,

y+44.01x=37.440

Solving the two equations, we get :

Mass_{Container}=y=37.025\ g

x = 0.00943 moles

Thus, Given:

Mass_{Container}+Mass_{Unknown\ gas}=37.062\ g

37.025\ g+Mass_{Unknown\ gas}=37.062\ g

Mass of the gas = 0.037 moles

Moles = 0.00943 moles

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.00943\ moles= \frac{0.037\ g}Molar mass}

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7 0
2 years ago
George splits a bagel in half and places both sides of the bagel in a toaster. He turns on the toaster, and within a minute the
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In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke
kondor19780726 [428]

Answer:

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q ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable  until q = Keq

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