Answer:
The specific heat capacity of liquid and the het of vaporization is used.
.
Explanation:
Step 1: Data given
A substance at temperature 2°C.
The substance has a melting point of −10°C and a boiling point of 155°C.
The initial temperature is 2°C which is between the melting point (-10°C) and the boiling point (155°C). At 2°C, the substance is liquid.
At 155°C, the substance changes from liquid to gas.
To calculate the heat gained for the change of 2°C liquid to 155°C liquid, specific heat capacity of the liquid (C) is needed.
To calculate the heat gained for the change of liquid to 155°C gas, heat of vaporization (D) is needed.
The <u>specific heat of the solid is not used</u> because the substance is changed from liquid to gas. it doesn't come in the state of solid.
<u>Heat of fusion is not used</u>, because it's used when there is a change from its state from a solid to a liquid,
<u>The specific heat capacity of the gas is not used</u>, because the substance only formes gas after reaching 155 °C
Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
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Answer:
Explanation:
we know that
ΔH=m C ΔT
where ΔH is the change in enthalpy (j)
m is the mass of the given substance which is water in this case
ΔT IS the change in temperature and c is the specific heat constant
we know that given mass=2.9 g
ΔT=T2-T1 =98.9 °C-23.9°C=75°C
specific heat constant for water is 4.18 j/g°C
therefore ΔH=2.9 g*4.18 j/g°C*75°C
ΔH=909.15 j
Answer:
<h2>The answer is 1.48 L</h2>
Explanation:
In order to find the original volume we use the same for Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the original volume
From the question
P1 = 172 kPa = 172000 Pa
P2 = 85 kPa = 85000 Pa
V2 = 3 L
We have
We have the final answer as
<h3>1.48 L</h3>
Hope this helps you
