Answer:
0.0198 lbs per gallon
Step-by-step explanation:
amount of salt free water = 500 gallons
salt rate in = 1 gal/min
salt rate out = 1 gal/min
amount o salt in brine = 0.25 lb per gallon
Let the amount of salt in the tank be A(t) at any time t.

salt rate in = 0.25 x 1 = 0.25
salt rate out =
The differential equation is given by

where, A(0) = 0
So, the equation becomes

Here the integrating factor is 
The solution of the above differential equation is given by


where, C is the integrating constant.

Put, A(0) = 0
C = - 500

As concentration is defined as
Concentration = Quantity / Volume


Now concentration at t = 10 min
Put, t = 10 min

C (10) = 0.0198 lbs per gallon
Thus, teh concentration after 10 min is 0.0198 lbs per gallon.