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irina1246 [14]
1 year ago
9

Hiros family lives 448 kilometers from the beach.Each of the 5 adults drove the family van an equal distance to get to and from

the beach.How far did each adult drive?
Mathematics
1 answer:
Drupady [299]1 year ago
3 0

Answer:

179.2km

Step-by-step explanation:

The distance from their house to the beach is 448km. Now they have to drive to and from the beach. The total distance traveled by the family is 448km + 448km.

This is equal to 896km. Now we have 5 adults who took their turns to drive and they drove the same distance. The total distance traveled by each adult will be 896/5 = 179.2km

Hence, each adult in the family drove a distance of 179.2km

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Divide 169 mi in the ratio 5 : 8.
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The answer is 169/5:8 = 5. It helps me alot it could help you to.
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A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally. A piece of climbing equipment at a
Dahasolnce [82]

Answer: The comparison is mentioned below.

Step-by-step explanation:

A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally.

Therefore its slope = length of the equipment vertically / length of equipment horizontally

m_1=  6/4 = 3/2 = 1.5

And, A piece of climbing equipment at a gym is 10 feet high and extends 6 feet horizontally.

Therefore slope, m_2=  10/6 = 5/3=1.67 (approx)

Since, m_1<m_2

Thus the slope of equipment first is less than slope of second equipment.


5 0
1 year ago
Read 2 more answers
Jenna eats dinner at a restaurant. Her bill is $14.50 Jenna pays her bill and leaves a tip. Write an inequality to represent the
Sophie [7]

Answer:

Step-by-step explanation:

x>14.50+y

7 0
2 years ago
Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte
xz_007 [3.2K]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.  

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

5\%=\frac{5}{100}=0.05  

When compounded annually, n=1:

A=4500(1+\frac{0.05}{1})^{1\cdot 10}

A=4500(1.05)^{10}

A=4500(1.6288946267774414)

A=7330.025820498\approx 7330.03

When compounded quarterly, n=4:

A=4500(1+\frac{0.05}{4})^{4\cdot 10}

A=4500(1.0125)^{40}

A=4500(1.6436194634870132)

A=7396.28758569\approx 7396.29

When compounded monthly, n=12:

A=4500(1+\frac{0.05}{12})^{12\cdot 10}

A=4500(1.00416666)^{120}

A=4500(1.64700949769)

A=7411.542739605\approx 7411.54

When compounded daily, n=365:

A=4500(1+\frac{0.05}{365})^{365\cdot 10}

A=4500(1.0001369863013699)^{3650}

A=4500(1.6486648137656943695)

A=7418.9916619456\approx 7419.00

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

4 0
2 years ago
Compare and contrast the solutions of 2x-4&gt;6 and 2x-4=6
elena55 [62]
2x-4=6
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for the inequality, however:
<span>2x-4>6 
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8 0
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