Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
The time of a commercial airplane is
t+140=140+140=280 minutes
Answer:

Step-by-step explanation:
<em>Subtract the students who don't have protractors from the students who have mathematical instruments.</em>

4 ducks (4 heads, 8 legs) and 2 sheep (2 heads, 8 legs). Altogether, 6 heads and 16 legs.
Answer:
Option C. $6,012
Step-by-step explanation:
we know that
The formula to calculate the depreciated value is equal to

where
V is the the depreciated value
P is the original value
r is the rate of depreciation in decimal
t is Number of Time Periods
in this problem we have
t = 7 years
P = $8,000
r = 0.04
substitute in the formula above

Hope this helps :)