Answer:
Step-by-step explanation:
a) sum of angle on the straight line TRW is 180.
Given <TRS = 2x+10
<SRW = x-10
<TRS+<SRW = 180
2x+10+x-10 = 180
3x = 180
x = 180/3
x = 60°
<TRV = 180°-(2x+10)
Substitute x = 60° into the expression
<TRV = 180-(2(60)+10)
<TRV = 180-(120+10)
<TRV = 180-130
<TRV = 50°
2) From the diagram attached <MHJ= <LHK (oppositely directed angle)
Given
<MHJ= x+15
<LHK = 2x-20
Substitute the given data into the formula to get x
x+15= 2x-20
x-2x = -15-20
-x = -35
x = 35°
Next is to get the measure of <MHJ
<MHJ = x+15
<MHJ = 35+15
<MHJ = 50°
Answer:
5.14 mi/h
Step-by-step explanation:
To find the average speed, we simply find the total distance traveled by Tom and divide that by the total time the entire journey took him.
Average speed = (total distance traveled) / (total time taken)
TOTAL DISTANCE TRAVELED
He traveled 3 miles to and 3 miles fro. Hence:
3 + 3 = 6 miles
TOTAL TIME TAKEN
He spent ½ hr to go and ⅔ hr to return back. Hence:
½ + ⅔ = 7/6 hr
Therefore, the average speed is:
v = 6 / (7/6)
v = 36 / 7 = 5.14 mi/h
Tom's average speed was 5.14 mi/h.
The area of the trapezoid can be calculated through the equation,
A = (b₁ + b₂)h / 2
where b₁ and b₂ are the bases and h is the height. Substituting the known values from the given,
A = (25mm + 32mm)(15 mm) / 2
A = 427.5 mm²
Since there are two trapezoids in the necklace, the area calculated is to be multiplied by two to get the total area.
total area = (427.5 mm²)(2)
<em>total area = 855 mm²</em>
Answer:
Kindly check explanation
Step-by-step explanation:
The alpha level set at the beginning of of an experiment is used by the researcher to the limit the probability if making a type 1 error. The type 1 error is committed when a true null hypothesis is incorrectly rejected.
The type 2 error on the other hand is committed when fail to reject a false null hypothesis.
Hence, in other to forestall the risk of incorrectly rejecting a true null hypothesis, the alpha level is set.
When critical region is split across both tails of the distribution, The z-score boundaries at an alpha level α = .05
α = .05 (95% confidence level)
When region is split into 2:
α/2 = .05/2
α/2 = 0.025
Loooking up the z table for the Zscore with probability of 0.025
Zscore = ±1.96
