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2 years ago

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A company has five warehouses, only two of which have a particular product in stock. A salesperson calls the five warehouses in

a random order until a warehouse with the product is reached. Let the random variable X be the number of calls made by the salesperson, and calculate its probability mass function and cumulative distribution function.

1 answer:

Kaylis [27]2 years ago

7 0

Answer: Check the attached

Step-by-step explanation:

You might be interested in

A college student is interested in testing whether business majors or liberal arts majors are better at trivia. The student give

attashe74 [19]

Answer:

There is no significant difference between the two averages at 5% level

Step-by-step explanation:

Given that a a college student is interested in testing whether business majors or liberal arts majors are better at trivia.

The student gives a trivia quiz to a random sample of 30 business school majors and finds the sample’s average test score is 86. He gives the same quiz to 30 randomly selected liberal arts majors and finds the sample’s average quiz score is 89

Thus he has done a hypothesis testing for comparison of two means of different subjects. n =30

$H_0: Mean of business majors = Mean of liberal arts majos\\H_a:Mean of business majors \neq Mean of liberal arts majos$

Since which is better is not claimed we use two tailed test here

We find that p value $= 0.0524 >5%$ our alpha

Since p >alpha, we find that there is no significant difference between the averages of these two groups and null hypothesis is accepted

4 0

2 years ago

The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent stud

yarga [219]

Answer:

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 60 \ hr$

The sample size is $n = 16$

The sample mean is $\= x = 68 \ hr$

The standard deviation is $\sigma = 20 \ hr$

The null hypothesis is $H_o : \mu = 60$

The alternative $H_a : \mu > 60$

Here we would assume the level of significance of this test to be

$\alpha = 5\% = 0.05$

Next we will obtain the critical value of the level of significance from the normal distribution table, the value is $Z_{0.05} = 1.645$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu}{ \frac{ \sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 68 - 60 }{ \frac{ 20 }{\sqrt{16} } }$

$t = 1.6$

Looking at the value of t and $Z_{\alpha }$ we see that $t< Z_{\alpha }$ hence we fail to reject the null hypothesis

This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course

So

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

6 0

1 year ago

To a survey of 290 newspaper reader, 181

astra-53 [7]

Question:

To a survey of 290 newspaper readers, 181 of them read the Daily Times, 142 Read the Guardian 117 read punch and each reads at least one of the three papers if 75 read the Daily Times, and the Guardian, 60 read the Daily Times and punch, and 54 read the Guardian and punch : Draw a Venn diagram to illustrate this information How many readers read All three papers ,Exactly two of the papers The Guardian alone?

Answer:

39 read all three news papers,72 Exactly two Papers & 52 reads Guardian Alone

Step-by-step explanation:

We have given, A survey of 290 newspaper readers.

Who read the Daily times A=181

Who read the Guardian times B=142

Who read the punch C=117

Who read Daily Times and the Guardian A\cap B= 75

Who read Daily Times and the punch A\cap C=60

Who read Guardian and punch B\cap C=54

To find :

How many readers read All three papers, Exactly two of the papers The Guardian alone?

Solution :

Readers read all three papers is $A\cap B\cap C$

Total survey is given by,

Total = $A+B + C- A\cap B- A\cap C - B\cap C+ A\cap B\cap C$

290 = $181 + 142 + 117 - 75 -60 - 54 +A\cap B\cap C$

290 = $251+A\cap B\cap C$

290-251= $A\cap B\cap C$

$A\cap B\cap C=39$

So, number of readers who read all three papers is 39.

Exactly two of the papers = 36 + 21 + 15 = 72

Guardian Alone = 52

7 0

2 years ago

Why did the queen have the king measure the rug

Alex73 [517]

Because he was such a good ruler

5 0

2 years ago

In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations wil

Virty [35]

Answer:

C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.

Step-by-step explanation:

The center for Simulation A and Simulation B will be roughly equal.

Overall Sample size of Simulation A = 1500 * 100 = 150000

Overall Sample size of Simulation B = 2000 * 50 = 100000

Since the sample size for Simulation A is greater, the variability of Simulation will be less.

Therefore, The answer is C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.

3 0

2 years ago