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Setler79 [48]
2 years ago
15

A company has five warehouses, only two of which have a particular product in stock. A salesperson calls the five warehouses in

a random order until a warehouse with the product is reached. Let the random variable X be the number of calls made by the salesperson, and calculate its probability mass function and cumulative distribution function.

Mathematics
1 answer:
Kaylis [27]2 years ago
7 0

Answer: Check the attached

Step-by-step explanation:

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What fraction is equal to75% of 1/2
GrogVix [38]

Answer:

3/8

Step-by-step explanation:

We can write 75% as a fraction, 75/100 and simplifying the fraction gives 3/4.

Then you have to multiply 1/2 * 3/4 which gives the result of 3/8.

3 0
2 years ago
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Which term describes the seller's ability and desire to sell goods and services? A. supply B. demand C. equilibrium
Leya [2.2K]

Answer:

A. supply

Step-by-step explanation:

The term that best describes the seller's ability and desire to sell goods and services out of given options is supply.

Buyer's willingness to buy a certain good at a certain price is defined as demand by most economists.

where as the seller's willingness to provide a certain good or service at a certain price is defined as supply by most economists. Supply does not merely means amount of goods supplied rather, for economists supply is a relationship between set of assigned prices and the amount of goods assigned to be sold at those prices.

hence the term that best describes the seller's ability and desire to sell goods and services out of given options is supply !

8 0
2 years ago
which represents the solution(s) of the system of equations, y=x^2-2x-15 and y=8x-40? determine the solution set algebraically
Harrizon [31]
y=x^2-2x-15 (1) y=8x-40 (2)

8x-40=x^2-2x-15
X^2+10x-25=0
(x-5)^2
×=5 y=0
7 0
2 years ago
Alejandro bought $3.50 worth of pencils and erasers at the school store. Pencils cost $0.50 apiece, and erasers cost $0.75 apiec
Natalka [10]
The correct answer is B

6 0
2 years ago
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Let ​ f(x)=x2+5x−36 ​. Enter the x-intercepts of the quadratic function in the boxes.
san4es73 [151]
Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-5*x-(36)=0 

Step by step solution:<span> Step 1:</span> Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-5x-36</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is 1.
The middle term is, <span> -5x </span> its coefficient is  - 5.
The last term, "the constant", is <span> -36 </span>

Step-1: Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2: Find two factors of  -36  whose sum equals the coefficient of the middle term, which is - 5.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9</span><span>     -9   +   4   =   -5   That's it</span></span>


Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  4 
                     <span>x2 - 9x</span> + 4x - 36

Step-4: Add up the first 2 terms, pulling out like factors :
                    x • (x-9)
              Add up the last 2 terms, pulling out common factors :
                    4 • (x-9)
Step-5: Add up the four terms of step 4 :
                    (x+4)  •  (x-9)
             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x + 4) • (x - 9) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     x = -4 

Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-9 = 0<span> 

 </span>Add  9  to both sides of the equation :<span> 
 </span>                     x = 9 

6 0
2 years ago
Read 2 more answers
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