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Answer:
<u>The correct answer is D. Any amount of time over an hour and a half would cost $10.</u>
Step-by-step explanation:
f (t), when t is a value between 0 and 30
The cost is US$ 0 for the first 30 minutes
f (t), when t is a value between 30 and 90
The cost is US$ 5 if the connection takes between 30 and 90 minutes
f (t), when t is a value greater than 90
The cost is US$ 10 if the connection takes more than 90 minutes
According to these costs, statements A, B and C are incorrect. The connection doesn't cost US$ 5 per hour like statement A affirms, the cost of the connection isn't US$ 5 per minute after the first 30 minutes free as statement B affirms and neither it costs US$ 10 for every 90 minutes of connection, as statement C affirms. <u>The only one that is correct is D, because any amount of time greater than 90 minutes actually costs US$ 10.</u>
Answer:
q = 108-n
Step-by-step explanation:
Given: 108 coins containing only quarters and nickels
q = 108-n
since total number of coins is 108, and n= number of nickels
If you want to know how many of each kind of coin, read on:
First solve the number of quarters and nickels.
If all 108 coins are quarters, the value is 108*0.25 = $27
Since this value exceed the actual by 27-21 = $6,
we replace a number of quarters by nickels.
Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.
So it will take 6/0.2 = 30 replacements.
Therefore there are 108-35 = 78 quarters and 30 nickels.
solution:
Consider the curve: r(t) = t²i +(int)j + 1/t k
X= t² , y = int ,z = 1/t
Using, x = t², z = 1/t
X = (1/z)²
Xz²= 1
Using y = int, z= 1/t
Y = in│1/z│
Using x = t², y = int
Y = int
= in(√x)
Hence , the required surface are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
