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cluponka [151]
1 year ago
11

Write a short discussion describing trends in the data: compare the control cups (distilled water) versus the experimental cups

(bicarbonate solution) and compare the light versus dark environments.
Biology
1 answer:
Eva8 [605]1 year ago
8 0

Answer:

The leaf discs only float in bicarbonate solution and in the light environment.

Explanation:

The bicarbonate dissolves in water to produce a source of inorganic CO2 in the reaction:

NaHCO3 + H2O → H2CO3 + OH- + Na+

Then, the HCO3- undergoes fixation through several complex steps in order to form a carbohydrate or sugar. These store the converted solar energy in their bonds as chemical energy to be used in metabolism.

Photosynthesis is a chemical process, essential to plant and other primary producers producing energy. Energy in the form of glucose molecules is derived from solar or light energy, water, and inorganic carbon dioxide, while it releases oxygen (from the light reaction). The leaf discs float as O2 gas is produced, making them buoyant.

6CO2 + 6H20 + (energy) → C6H12O6 + 6O2

Carbon dioxide + water + energy= glucose + oxygen

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Answer:

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Explanation:

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2 years ago
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6 0
1 year ago
"crabgrass preventer" is what type of herbicide? css 202
Anastaziya [24]
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2 years ago
Check your understanding
wel

The fraction of offspring with black coat color and straight fur is 9/16.

Explanation:

Information given:

black coat colour and straight fur - dominant genotype BBCC, BbCc

yellow coat colour and curly fur - recessive genotype  bbcc

Both the traits are independently assorted. The fur colour and fur type is not present on the same chromosome and are not sex linked.

The genotype of the parents are:

BbCc X BbCc

Punnet square shows:

          BC           Bc          bC        bc

BC  BBCC   BBCc        BbCC   BbCc

Bc  BBCc   BBcc          BbCc    Bbcc

bC BbCC    BbCc         bbCC   bbCc

bc  BbCc      Bbcc         bbCc    bbcc

9 BLACK STRAIGHT

 3 BLACK CURLY

 3 YELLOW STRAIGHT

  1  YELLOW CURLY

9/16 is the fraction of progeny to be black coat colour and straight fur.

5 0
1 year ago
Which of the following offspring genotypes could result from the fertilization of an egg that had undergone nondisjunction in me
Lorico [155]

Answer:

See explanation below

Explanation:

<em>Non-disjunction occur as a result of lack of separation of homologous chromosomes during meiosis. </em>

As a result, the gametes (the daughter cells formed) produced end up having extra or lesser chromosomes as compared to a normal gamete.

When a gamete with extra chromosome fertilizes a normal gamete, the resulting offspring will have an extra chromosome (trisomy condition).

On the other hand, when a gamete with one less chromosome than normal fertilizes a normal gamete, the resulting offspring will have one less chromosome than normal offspring (monosomy condition).

Assuming a chromosome with Aa gene undergoes non disjunction during meiosis, the resulting gametes either contain both A and a chromosome or contain no chromosome at all.

If Aa gamete is fertilized by a normal haploid sperm (a), the resulting zygote will have the genotype Aaa.

If a gamete with no chromosome at all fertilizes a normal haploid sperm, the resulting offspring will have the genotype a.

5 0
2 years ago
Read 2 more answers
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