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Misha Larkins [42]
2 years ago
5

Part A Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a ch

emical equation. Identify all of the phases in your answer. nothing Request Answer Part B Enter a net ionic equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a chemical equation. Identify all of the phases in your answer. nothing Request Answer

Chemistry
1 answer:
Basile [38]2 years ago
7 0

Answer:

2HNO3+Ca(OH)2 = Ca(NO3)2+2H2O

Explanation:

The reaction between Nitric acid(HNO3)and Calcium hydroxide(Ca(OH)2) gives Calcium Nitrate( Ca(NO3)2 and Water( H2O)

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The highest energy occupied molecular orbital in the b−b bond of the b2 molecule is _____
statuscvo [17]
According to molecular orbital theory, atomic orbitals combine to form molecular orbital. Number of molecular orbitals are equal to number of atomic orbitals. Further, of the total number of molecular orbitals, half are called as bonding molecular orbital while remaining are anti-bonding molecular orbital. In case, if system contains lone pair of electrons, they occupy non-bonding molecular orbital. Highest occupied molecular energy levels are referred as HOMO, while lowest unoccupied molecular energy levels are referred as LUMO.

In case of B2 molecule, two B atoms combines to generate molecular orbitals. Attached is  the MOT diagram of B2 molecule

From the attached figure, it is clearly evitable that high occupied energy level in B2 is π. Also, it must be noted both <span>pi molecular orbitals i.e. Pi 2Px and Pi 2Py at highest energy level (occupied).</span>

6 0
2 years ago
Read 2 more answers
Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid. MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l)
Marina CMI [18]

Answer:

Please see the complete formt of the question below

Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid.

MnO₂(s) + HCl(aq) → MnCl₂(aq) + H₂O(l) + Cl₂(g)

According to the above reaction, determine the limiting reactant when 5.6 moles of MnO₂ are reacted with 7.5 moles of HCl.

The answer to the above question is

The limiting reactant is the MnO₂

Explanation:

To solve this,  we note that one mole of MnO₂ reacts with one mole of HCl to produce one mole of MnCl₂, one mole of H₂O and one mole of Cl₂

Molar mass of MnO₂ = 86.9368 g/mol

Molar mass of HCl = 36.46 g/mol

From the stoichiometry of the reaction, 5.6 moles of MnO₂ will react with 5.6 moles of HCl to produce 5.6  moles of H₂O and 5.6 moles of Cl₂

However there are 7.5 moles of HCL therefore there will be an extra 7.5-5.6 or 1.9 moles of HCl remaining when the reaction is completed

7 0
2 years ago
The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is centr
pshichka [43]
<h3><u>Answer;</u></h3>

Cannon-Bard theory

<h3><u>Explanation</u>;</h3>
  • <em><u>The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is central to the Cannon-Band theory.</u></em>
  • Cannon-Bard theory states that we feel emotions and experience physiological reactions such as sweating, trembling, and muscle tension simultaneously.
  • The theory argues that we experience physiological arousal and emotion at the same time. The theory gives more attention to the role of thought or outward behavior as compared to James-Lange.
7 0
2 years ago
Read 2 more answers
If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79
Helen [10]
1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass. 

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol

200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4

3) convert moles of CuSO₄ to moles of Cu

1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu

4) convert moles of Cu to grams using it's molar mass.

molar mass Cu= 63.5 g/mol

1.25 mol (\frac{63.5 grams}{1 mol} )= 79.4 grams Cu

I did it step-by-step as the explanation but you can do all of this in one step. 

200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu


4 0
2 years ago
Panuto: Sumulat ng isang halimbawa ng adyenda. Ipagpalagay mo na ikaw ay isang tagapayo. Ikaw
Degger [83]

Answer:

Sumulat lamang ng mga random na pangalan at sabihin ang "Appointment with (name)"

School Counselor ba ito?

8 0
2 years ago
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