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masya89 [10]
2 years ago
8

A swim race has a total distance of 25 mi . Race officials want to mark the course every 500 yd with a buoy, including one at th

e finish line. (The starting line does not need a buoy.) How many buoys are needed
Mathematics
1 answer:
arsen [322]2 years ago
6 0

Answer:

I believe 88 buoys

Step-by-step explanation:

The race is 25 miles long and theirs a buoy every 500 yards

There are 44000 yards in 25 miles

44000 (yards) divided by 500 (yards) is 88 (buoys).

500 yards      44000 yards

--------------- =  --------------------

1 buoy              x buoys

Going diagonally, 1 × 44000 is 44000.

44000 ÷ 500 = x

x = 88

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The total number of possible 2-item combinations is (1000 choose 2)

The number of 2-defective combinations is (300 choose 2)

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In ΔIJK, i = 340 cm, ∠I=120° and ∠J=59°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.
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Four speed skaters, Marco, Naim, Oliver, and Pedro, compete in a relay race where they all agree that Naim will be the last
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Answer:

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Everyone has already agreed that Naim would be the last skater, so we have to make sure that the result has 'N' in each last place. As we can see, they all have this.

Now, we also have to make sure Oliver <u>not</u> first, because although they're trying to decide, the problem asks for the <u>complement</u> in which "Oliver is the first skater in the race."

A complement is all the values that are NOT in the set, so it cannot be A = {OPMN, OMPN) or A = {MOPN,MPON, OPMN, POMN), because they both have at least one case where 'O' is first.

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Read 2 more answers
Researchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a rando
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Answer:

a)

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b)

<em>D) The data come from a Population that is Normally distributed</em>

<em>F) the samples are independent</em>

<em>c) </em>

<em>Null hypothesis: H₀: </em>p_{m} ^{-} - p^{-} _{fm} \leq  0

<em>Alternative Hypothesis H₁</em>: p_{m} ^{-} - p^{-} _{fm} \geq  0

Step-by-step explanation:

Given data Among the 530 males​ surveyed, 175 responded​ "Yes

The sample proportion of males

p_{m} ^{-}  = \frac{x}{n} = \frac{175}{530} = 0.3301

The sample proportion of 575 Females surveyed, 218 responded​ "Yes

p_{fem} ^{-}  = \frac{x}{n} = \frac{218}{575} = 0.3791

a)

The proportions of the females and males who took the survey who are annoyed by the behavior in question are<u> 0.3301 </u>and_<u>0.3791 </u>respectively

b)

<em>The data come from a Population that is normally distributed.</em>

<em>The two samples are independent</em>

c)

<em>Null hypothesis: H₀: </em>p_{m} ^{-} - p^{-} _{fm} \geq 0

<em>Alternative Hypothesis H₁</em>: p_{m} ^{-} - p^{-} _{fm} \leq  0

We will use two samples Z - hypothesis test

Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }

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Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301)  }{530 }+\frac{0.3791(1-0.3791)}{575}  }

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The null hypothesis is accepted

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The evidence suggest not a higher proportion of females are annoyed by this​ behavior

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